y. ov(X₁, Y₁) = 0²/2. (D;) and Var(D;). test for Ho: x=y which uses the test statistic Z = √nD. jects Ho, if and only if |Z| > 1.96. Show that P(type I error) ee sentences, discuss the differences between the test from part e non-paired test for comparing the means of two populations
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- The population of healthy female adults, the mean red blood cell count (RBC) is 4.8 (millions of cells per cubic millimeter of whole blood). A researcher thinks the RBC is underestimated, so she conducts a test of significance using Null Hypothesis: µ ≤ 4.8 vs. Alternative Hypothesis: µ >4.8. If the true mean RBC is 4.75 and the null hypothesis is rejected, out of the four options below, what has occured? Type 1 Error, Type 2 Error, No error, OR can’t tell without knowing the degrees of freedom?16can you please provide explanations
- A sample of 33 lights in Austin gives an average of 46 cars/min while the city SD=3.4 A sample of 34 Dallas lights give a mean of 44 cars/mim with the city SD=1.4 At the 91% level, do the towns differ? 1. Is the test (A-Left Tailed, B-Right Tailed, C-2-Tailed) (separate with comma if there are 2) 2. Critical Value 3. Test statistic 4. 3-decimal p-ValueThe effectiveness of surgery for weight loss reported here found that "The surgery was associated with significantly greater weight loss [than the control group who dieted] through 2 years (61.3 versus 11.2 pounds, P<0.001)." What test could have been used and how would it have been computed?The Wilcoxon signed-rank test can be used to perform a hypothesis test for a population median, η, as well as for a population mean, µ. Why is that so?
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- I need help finding the test statistic and the P-valueIID Suppose X1, ..., X, N(u, o?). Construct a 95% confidence interval for o? when u is known.1.A chi-square test for independence is being used to evaluate the relationship between two variables, one of which is classified into 2 categories and the second of which is classified into 4 categories. What is the df value for the chi-square statistic? a. df = 2 b. df = 6 c. df = 7 d. df = 3