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y" + (x - 3)y' = 0 Plug in the appropriate power series for "y" and "y'" in order to convert the differential equation into a power series. 00 E (n - 1)A,x(n - 2) E na, x(a - 1) EA,x" = 0 n = 2 n =0 00 00 Σ 00 ® E» (n – 1) A, xln - 2) + 2 nA, x" 3n A x(" - 1) = o n = 2 00 En (n - 1) A, x( - 2) E (x - 3) n A x(u - 1!) = 0 n = 2 n = 1 O E- (n - 1) A, x(u - 2) - E 3 n A, xla - 1) 2 3n A x(" - 1) n = 2 00 E n (n – 1) (x – 3) A, xu - 3) = 0 n = 2

y" + (x - 3)y' = 0 Plug in the appropriate power series for "y" and "y'" in order to convert the differential equation into a power series. 00 E (n - 1)A,x(n - 2) E na, x(a - 1) EA,x" = 0 n = 2 n =0 00 00 Σ 00 ® E» (n – 1) A, xln - 2) + 2 nA, x" 3n A x(" - 1) = o n = 2 00 En (n - 1) A, x( - 2) E (x - 3) n A x(u - 1!) = 0 n = 2 n = 1 O E- (n - 1) A, x(u - 2) - E 3 n A, xla - 1) 2 3n A x(" - 1) n = 2 00 E n (n – 1) (x – 3) A, xu - 3) = 0 n = 2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the following differential equation y" + (x - 3)y' = 0 Plug in the appropriate power series for "y" and "y" in order to convert the differential equation into a power series. 00 A En (n - 1) A, x" - 2) E na, xla - 1) ΣΑ A x" n = 2 n = 1 n =0 2n (n – 1) A xlu – 2) Σ Σ B 2 n A x" 3 n A x" - 1) = 0 n = 2 n = 1 n = 1 00 En (n - 1) A xln - 2) E (x - 3) n A x(" - 1) = 0 n = 2 n = 1 O i (u - 1)4, al -) - an4,al-) - -- 00 D n = 2 En (n – 1) A, x(« - 2) Σ 3nΑ x-1) n = 1 00 En (n - 1) (x - 3) A, x(u - 3) = 0 n = 2
Transcribed Image Text:Given the following differential equation y" + (x - 3)y' = 0 Plug in the appropriate power series for "y" and "y" in order to convert the differential equation into a power series. 00 A En (n - 1) A, x" - 2) E na, xla - 1) ΣΑ A x" n = 2 n = 1 n =0 2n (n – 1) A xlu – 2) Σ Σ B 2 n A x" 3 n A x" - 1) = 0 n = 2 n = 1 n = 1 00 En (n - 1) A xln - 2) E (x - 3) n A x(" - 1) = 0 n = 2 n = 1 O i (u - 1)4, al -) - an4,al-) - -- 00 D n = 2 En (n – 1) A, x(« - 2) Σ 3nΑ x-1) n = 1 00 En (n - 1) (x - 3) A, x(u - 3) = 0 n = 2
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