y" (x) = 2y(x) + 2[y(x)]° with y(0) = 0 and y'(0) = 1.

Q: Find y as a function of a if y(0)2, y'(0) = 3, "(0) = -13. y(x) = y″ − 4y″ − y′ + 4y = 0,

A: Given a differential equation:initial conditions are:

Q: ' (x² +2)+4x(y² +2y+1)=0, y(0) =1.

A:

Q: If a(x) = 2 – 8x, what is an equation for a (x)? O A. a-1(x) 2. 8. O B. a '(x) = ?= 2 8 al(z) = ", 으…

A: The given equation for a(x) is: a(x)=2-8x

Q: Find y' and y". In(7x) y = x7 y' = y" %3D

A: The given function is: y=ln(7x)x7 Therefore, y'=1x7ddx(ln(7x))+ln(7x)ddx1x7    =1x717x·7+ln(7x)-7x8…

Q: Find y as a function of x if x'y" + 5xy' + 4y = 0, y(1) = 9, y'(1) = -2. y =

A: Solution :-

Q: Find y' and y". y': y" = y = (²+ √x) ³

A: SOLUTION-

Q: Find f'(x), f''(x), and f (x) for the following function. f(x) = 9x° + 5x2 + 8x %3D

A: differentiate wrt to x

Q: If R'(x)=250-18x and R(0)=0, find R(x)

A:

Q: 1२ '२ 12 factoo

A:

Q: 33 + 5f(x)+7²(f(x))° = 0 and f(-2) = –1, find f'(-2).

A:

Q: Find y'" for y=eto y" =D + 11x.

A: Given y=ex3+11x

Q: If xy? - y3 = 5, find y'. y' =

A:

Q: Find y as a function of a if y(1) = -4, y'(1) = -9. y x²y" + 2xy' - 6y = 0,

A:

Q: Find y as a function of a if y(1) = 8, y'(1) = 6. y = x²y" + 3xy' - 35y = 0,

A:

Q: Find y as a function of a if y(0) = 6, y'(0) = 24, y"(0) = 108. y" + 36y' = 0,

A: y′′′+36y′=0y(0)=6,y′(0)=24,y′′(0)=108.The characteristic equation…

Q: Find y' and y". In(3x) y = y" %3!

A: Given y=ln3xx6

Q: Find y' (-1) if y = In (a² + 5)° (2 – 4æ)®

A: I have stated the used formulas in the solution

Q: Answer: y = -(e-x + c)/(1 + x2)

A: Given differential equation is,

Q: Find y as a function of if y(0) = 19, y'(0) = 19, y"(0) = 4, y"(0) = 0. y(x) = y(4) 4y" + 4y = 0,

A: y(4)−4y′′′+4y′′=0y(0)=19,y′(0)=19,y′′(0)=4,y′′′(0)=0

Q: find y as a function of x if y'" + 81y' - = 0 where y(0) = 1, y'(0) = 81, y"(0) = 324

A:

Q: y'(x) у(1) — 0

A:

Q: Given that f(x) = 4x+9 and g(x)=x°, find (fo g)(-5). (fo gX-5)-

A:

Q: Find y'(2)  y=ex2−ay=ex2−a where a=4

A:

Q: Find an equation of the line tangent to the graph of ​G(x)=3e−2x at the point ​(0,3​).   y=

A:

Q: factor 3x^3+18x^2+27x

A: We have