Y ºX For the projectile above, what is the acceleration at Point Y?

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### Physics Quiz Question

What is the acceleration due to gravity on Earth?

**Options:**

1. \( -9.8 \, \dfrac{m}{s^2} \)

2. \( 0 \, \dfrac{m}{s^2} \)

3. \( 9.8 \, \dfrac{m}{s^2} \)

4. not enough information
Transcribed Image Text:### Physics Quiz Question What is the acceleration due to gravity on Earth? **Options:** 1. \( -9.8 \, \dfrac{m}{s^2} \) 2. \( 0 \, \dfrac{m}{s^2} \) 3. \( 9.8 \, \dfrac{m}{s^2} \) 4. not enough information
### Analyzing Projectile Motion

**Question:**
For the projectile above, what is the acceleration at Point Y?

**Explanation:**
In the provided diagram, a character is depicted throwing a projectile. The trajectory of the projectile is traced with a dashed line, marking its path through the air. The path curves upwards, reaches a peak marked as Point Y, and then descends back down. Three key points, X, Y, and Z, are labeled along the path to indicate specific stages in the projectile’s flight. Point Y is highlighted within a red circle, suggesting it is the apex or highest point of the projectile’s trajectory.

**Key Concepts in Projectile Motion:**

1. **Horizontal and Vertical Components of Motion:**
   - In projectile motion, the horizontal and vertical motions occur simultaneously but independently of each other.
   - The horizontal velocity remains constant as there are no external forces acting horizontally if we neglect air resistance.
   - The vertical velocity is influenced by the acceleration due to gravity (g), which acts downwards.

2. **Acceleration Due to Gravity:**
   - Throughout the projectile’s flight, only one acceleration acts on the projectile, which is the acceleration due to gravity (approximately \(9.8 \, \text{m/s}^2\)).
   - This acceleration is directed downwards at all points in the projectile’s trajectory, including Point Y.

3. **At the Apex (Point Y):**
   - At the apex or highest point of the trajectory (Point Y), the vertical component of the velocity is zero.
   - However, even though the vertical velocity is momentarily zero, the acceleration due to gravity continues to act downward.

**Conclusion:**
At Point Y, the acceleration of the projectile is \(9.8 \, \text{m/s}^2\) downward. Thus, the projectile experiences a constant downward acceleration due to gravity at all points along its path, including at the highest point.
Transcribed Image Text:### Analyzing Projectile Motion **Question:** For the projectile above, what is the acceleration at Point Y? **Explanation:** In the provided diagram, a character is depicted throwing a projectile. The trajectory of the projectile is traced with a dashed line, marking its path through the air. The path curves upwards, reaches a peak marked as Point Y, and then descends back down. Three key points, X, Y, and Z, are labeled along the path to indicate specific stages in the projectile’s flight. Point Y is highlighted within a red circle, suggesting it is the apex or highest point of the projectile’s trajectory. **Key Concepts in Projectile Motion:** 1. **Horizontal and Vertical Components of Motion:** - In projectile motion, the horizontal and vertical motions occur simultaneously but independently of each other. - The horizontal velocity remains constant as there are no external forces acting horizontally if we neglect air resistance. - The vertical velocity is influenced by the acceleration due to gravity (g), which acts downwards. 2. **Acceleration Due to Gravity:** - Throughout the projectile’s flight, only one acceleration acts on the projectile, which is the acceleration due to gravity (approximately \(9.8 \, \text{m/s}^2\)). - This acceleration is directed downwards at all points in the projectile’s trajectory, including Point Y. 3. **At the Apex (Point Y):** - At the apex or highest point of the trajectory (Point Y), the vertical component of the velocity is zero. - However, even though the vertical velocity is momentarily zero, the acceleration due to gravity continues to act downward. **Conclusion:** At Point Y, the acceleration of the projectile is \(9.8 \, \text{m/s}^2\) downward. Thus, the projectile experiences a constant downward acceleration due to gravity at all points along its path, including at the highest point.
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