An artilery shell is fired with un Initial velocity of 300 m/s at 45.0° above the horizontal. To clear an avalanche, It explodes on a mountalnside 41.5 s after firing. What are the x- and y-coordinates of the shel where it explodes, relative to its firing point? *************............ ... ..... *.................... 3. Subm Arawet
An artilery shell is fired with un Initial velocity of 300 m/s at 45.0° above the horizontal. To clear an avalanche, It explodes on a mountalnside 41.5 s after firing. What are the x- and y-coordinates of the shel where it explodes, relative to its firing point? *************............ ... ..... *.................... 3. Subm Arawet
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Projectile Motion Problem**
An artillery shell is fired with an initial velocity of 300 m/s at an angle of 45.0° above the horizontal. To clear an avalanche, it explodes on a mountainside 41.5 seconds after firing. What are the x- and y-coordinates of the shell when it explodes, relative to its firing point?
**x =** ___ m
**y =** ___ m
*[Submit Answer]*
This problem involves the application of kinematic equations to determine the coordinates of a projectile at a given time. Typically, you would use the initial velocity, angle, and time to calculate both the horizontal (x) and vertical (y) positions using the following formulas:
- \( x = v_0 \cdot t \cdot \cos(\theta) \)
- \( y = v_0 \cdot t \cdot \sin(\theta) - \frac{1}{2} g t^2 \)
Where:
- \( v_0 \) is the initial velocity (300 m/s in this case).
- \( \theta \) is the launch angle (45.0°).
- \( t \) is the time (41.5 s).
- \( g \) is the acceleration due to gravity (approximately 9.81 m/s²).
Solve these equations to find the precise x and y coordinates at the moment of explosion.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F212f1a9d-c23e-4230-9cf0-4b21895c9148%2F15fbb268-b916-443f-84d5-8d678ac92775%2Fabbzlhg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Projectile Motion Problem**
An artillery shell is fired with an initial velocity of 300 m/s at an angle of 45.0° above the horizontal. To clear an avalanche, it explodes on a mountainside 41.5 seconds after firing. What are the x- and y-coordinates of the shell when it explodes, relative to its firing point?
**x =** ___ m
**y =** ___ m
*[Submit Answer]*
This problem involves the application of kinematic equations to determine the coordinates of a projectile at a given time. Typically, you would use the initial velocity, angle, and time to calculate both the horizontal (x) and vertical (y) positions using the following formulas:
- \( x = v_0 \cdot t \cdot \cos(\theta) \)
- \( y = v_0 \cdot t \cdot \sin(\theta) - \frac{1}{2} g t^2 \)
Where:
- \( v_0 \) is the initial velocity (300 m/s in this case).
- \( \theta \) is the launch angle (45.0°).
- \( t \) is the time (41.5 s).
- \( g \) is the acceleration due to gravity (approximately 9.81 m/s²).
Solve these equations to find the precise x and y coordinates at the moment of explosion.
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