y' - 5y = f(t), where f(t) = ft², lo. 0≤t<1 1≥ l' y(0) = 1

Q: 1 Y(s) 4 5s2 S

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Q: Find f'(x). Vx- 3 f(x) =

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Q: 3. Find f. 1 (d) f'(x) = (e) f'(x) = 5 (f) f'(t) = at + vo

A: To find the function f from its derivative,integrate f'  with respect to the given variable. Use the…

Q: The first derivative of a continuous function y = f(x) is y' = x(x - 27)². Find y" and then use the…

A: Introduction: The first derivative's current rate of change is gauged by the second derivative. We…

Q: Let  f(x)=x^5/e^x. Find f'(5).

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Q: Let h(x) = 300s a. Find h'(x) and also h'(T/2).

A: The given function is: h(x)=3cos x

Q: Find h' (1) for the function h(x) = f(x)f(x). h'(1) = f(1) = 5 and f'(1) = 1.

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Q: y y' + (2х + 3у) = 0 y(x) = ? =>

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Q: Let f(r) 3 sec(5z) %3D f'(x) =

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Q: Find f'(x) for f(x) = 3 arctan(4x² – 3) %3D

A: we use the formula f'(x) of arcton x=1/1+x^2.

Q: Find f' where f(x) = ln(x²-2x)

A: We have to find  for the following functionWe know that

Q: Let f(x) = x' - 2x. Find: %3D (a) f'(x) (b) f'(-1), f'(1). f (2)

A: Given that f(x)=x2-2x

Q: Find f'(x). Vx-3 f(x) = f'(x) = %3D

A: Given function  fx=ex-3 To differentiate given function chain rule is used ,chain rule is defined as…

Q: Find f'(x) for f(x) = 8x°e*. f'(x) = Preview

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Q: Find f'(x) and f'(c). Function Value of c x² – 4 f(x) = C = 1 %3D х — 8

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Q: Find f. f'(x) = 8x – 3/x*, x > 0, f(1) = 7 - f(x) =

A: Our objective is to find f.  Since you have posted multiple questions. We will answer only one. If…

Q: The tangent line to the graph of y = f(x) at the point (3, 12) has the equation y = 2x + 6. (a) Find…

A: Consider the given tangent line:

Q: Find f'(x). Vx- 19 f(x) = e %3D

A: Given,            f(x) = ex-19

Q: The rate at which users join is R'(t)=_.36t^2+3.84t+0.46 where t is months from (0<t<10) if there…

A: It is given that, the rate at which users join is R'(t)=_.36t^2+3.84t+0.46 where t is months from…

Q: Find f'(x) for f(x) = e* - 5x.

A: Given : fx =e4x2-5x

Q: Find f'(x), where f(x) = xV4- a°. | f'(x) = %3D

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Q: F(x) = [ 2 1 | t dt

A: topic - integration and derivative we are given F(x)=∫2x1tdtwe know that∫1xdx=ln|x| +Cddxln(x)=1x

Q: Find h'(x) given that h(x) = Vx² +1

A: To do this problem we need chain rule  Chain Rule (using ’ ) f'(g(x))= f’(g(x))  g’(x) We will use…

Q: Find f. f'(x) %3D 6х — 3/x*, х> 0, f(1) %3D 6

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Q: Let f(x) = 4 sec '(4x). Find f'(x). f'(x) = Find f'(5). f'(5) =

A: