(2) For what values of a does the graph of the following function have a horizontal tangent line? d dx t f(x) = x²e-2x f'(x)= = -2x28 = x²e-2x te=²x2x こ 2 -2x e لے x²=//=²²*² +6²-²x + / +² +2 d te 2 dre Jx с +² +2x 2x -2x e = x (x + 2) 2 X x(x+2) e 2+ +(x+2) e = 0 -200
(2) For what values of a does the graph of the following function have a horizontal tangent line? d dx t f(x) = x²e-2x f'(x)= = -2x28 = x²e-2x te=²x2x こ 2 -2x e لے x²=//=²²*² +6²-²x + / +² +2 d te 2 dre Jx с +² +2x 2x -2x e = x (x + 2) 2 X x(x+2) e 2+ +(x+2) e = 0 -200
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:f'(x) == x+² é'
2
dx
e
(2) For what values of x does the graph of the following function have a horizontal tangent line?
f(x) = x²e-2x
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dx
= x²e-2x te-2x zx
-2x
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-2x
+² +2x
e²x
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2X
-2x
te
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Jx
+
2
x(x+2)
24
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x(x+2Je
-200
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I'm just curious as to where the -2 came from?
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