wn Decming ore PessesSketch the region enclosed by the given curves.y = 14 - x2, y = x2 - 4yyyy15-5-5-15|The xy-coordinate planis gien. Tere are2 curves and aregion on the grph.• The first curenters the windown e thirdquadrant, goVp and0Fht becong less steep,Ais at appfoximatel10-6-42246-6-4-2246.crosses thethrough thesecond curv ngesgoes down nd ht becemingthrough th appisecond cuve= -3.7, passesoximaterpoint (-/9) crossing therection th point (0, 14),eep, passes2.2, 9crossing theExis at appximatelyadrant.-5-555oina Cve, crosseh= 3.7,nd exits theThe second curve enterquadran goes downpasses hrough the appe fouth quasecondess steep,9)inindow inbecoximate point- 10- 10-66-6 0, -Aoes ue 2throuh the apprfirst urve, and exitsThe egion occurs belowsecchd curve.2 mor(2.2,ow in the first uadrant.rst curve and aove theing the- 15F-15-5-Find the area of the region.

y= 14 - x?, y = x² - 4 y y 15 15 The y coordinla region on the gph The first cun e quadrant, go/a 10 crosses the apimate X , passes through the /Aatoint (A crossing the second cur goes downnd t becmingoreep, re are and a indo ethird eco esssteep --37, passes 10 -6 -6 -2 2 4 oximately ges ection poin /nt o, 14) -5 cond 5 rosng the mately through app foth quadrant second -10 -10 -6 -6 -2 pa 6 the adrant ove the The ic -15 15H

y= 14 - x?, y = x² - 4 y y 15 15 The y coordinla region on the gph The first cun e quadrant, go/a 10 crosses the apimate X , passes through the /Aatoint (A crossing the second cur goes downnd t becmingoreep, re are and a indo ethird eco esssteep --37, passes 10 -6 -6 -2 2 4 oximately ges ection poin /nt o, 14) -5 cond 5 rosng the mately through app foth quadrant second -10 -10 -6 -6 -2 pa 6 the adrant ove the The ic -15 15H

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Concept explainers

Riemann Sum

Riemann Sums is a special type of approximation of the area under a curve by dividing it into multiple simple shapes like rectangles or trapezoids and is used in integrals when finite sums are involved. Figuring out the area of a curve is complex hence this method makes it simple. Usually, we take the help of different integration methods for this purpose. This is one of the major parts of integral calculus.

Riemann Integral

Bernhard Riemann's integral was the first systematic description of the integral of a function on an interval in the branch of mathematics known as real analysis.

Question

wn Decming ore Pesses
Sketch the region enclosed by the given curves.
y = 14 - x2, y = x2 - 4
y
y
y
y
15-
5-
5-
15|
The xy-coordinate planis gien. Tere are2 curves and a
region on the grph.
• The first curenters the windown e third
quadrant, goVp and0Fht becong less steep,
Ais at appfoximatel
10
-6
-4
2
2
4
6
-6
-4
-2
2
4
6.
crosses the
through the
second curv nges
goes down nd ht beceming
through th appi
second cuve
= -3.7, passes
oximaterpoint (-/9) crossing the
rection th point (0, 14),
eep, passes
2.2, 9crossing the
Exis at appximately
adrant.
-5
-5
5
5oin
a Cve, crosseh
= 3.7,
nd exits the
The second curve enter
quadran goes down
passes hrough the app
e fouth qua
second
ess steep,
9)
in
indow in
beco
ximate point
- 10
- 10
-6
6
-6 0, -Aoes ue 2
throuh the appr
first urve, and exits
The egion occurs below
secchd curve.
2 mor
(2.2,
ow in the first uadrant.
rst curve and aove the
ing the
- 15F
-15
-5-
Find the area of the region.

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