When you stand in shallow water and look at an object below the surface of the water, the object will look farther away from you than it really is. This is because when light rays pass between air and water, the water refracts, or bends, the light rays. The index of refraction for water is 1.333. This is the ratio of the sine of e, and the sine of e, (see figure). (a) While standing in water that is 2 feet deep, you look at a rock at angle e, = 50° (measured from a line perpendicular to the surface of the water). Find e, in degrees. (Round your answer to one decimal place.) e2 = (b) Find the distances x and y, in feet. (Round your answers to two decimal places.) ft y = ft (c) Find the distance d (in ft) between where the rock is and where it appears to be. (Round your answer to two decimal places.) d- ft (d) What happens to d as you move closer to the rock? Explain. O As you move closer to the rock, d must get larger and larger. The angles e, and e, will decrease as the distance y increases, so d will increase. O As you move closer to the rock, d must get smaller and smaller. The angles e, and e, will decrease along with the distance y, so d will decrease. O As you move closer to the rock, d must get larger and larger. The angles e, and e, will increase along with the distance y, so d will increase. O As you move closer to the rock, d must get smaller and smaller. The angles e, and e, will increase as the distance y decreases, so d will decrease. O As you move closer to the rock, d does not change. The angles e, and e, will remain the same along with the distance y, so d will also remain the same. O O i 22:07