y 1. A non-conducting rod of lengthl with a uniform charge density A and a total charge Q is lying along the x -axis, as illustrated in the Figure. The electric field at a point P, located at a distance y off the axis of the rod is:
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A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts (a, b,…
Q: In the figure a nonconducting rod of length L = 8.20 cm has charge -q = -4.23 fC uniformly…
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Q: Question no 1: A non-conducting rod of length A with a uniform charge density à and a total charge Q…
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A: (a) ρ=ρ0e-r/aQ=∫0rρdVQ=∫0rρ0e-r/a(4πr2dr)Q=4πρ0∫0re-r/ar2drQ=4πρ0 [2a3-(ar2+2a2r+2a3)e-r/a]From…
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A: (a) The linear charge density of the rod will be:
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- Which of the following charge distributions will generate a uniform electric field at the specified distance? Select all that apply. a) A distance r from the center of a long, thin line of uniform charge with length L where r << L. b)A distance r away from a large disc of uniform charge (with radius R) where r << R (and not near the edge of the disc) c)A distance r away from a sheet of uniform charge (with dimensions a x a) where r << a (and not near the edge of the sheet). d)Any point between two infinitely large sheets of uniform charge, one with total charge +Q and the other with total charge -Q. e)A distance r from the center of a sphere of uniform charge (with radius R) where r >> R. f)Halfway between two infinitely large sheets of uniform charge, each with total charge -Q.A Line Of Uniform Charge Q Runs Along The Y-Axis From 0 To L. What is the electric field at the position (x0, y0)?You place a known amount of charge Q on the irregularly shaped conductor . If you know the size and shape of the conductor, can you use Gauss’s law to calculate the electric field at an arbitrary position outside the conductor?
- A ring of radius R has total charge Q.a) At what distance along the central axis perpendicular to the plane of the ring is the electric field strength a maximum?b) What is the electric field strength at this point?In the figure a nonconducting rod of length L = 8.42 cm has charge -q = -4.46 fC uniformly distributed along its length. (a) What is the linear charge density of the rod? What are the (b) magnitude and (c) direction (positive angle relative to the positive direction of the x axis) of the electric field produced at point P, at distance a = 15.4 cm from the rod? What is the electric field magnitude produced at distance a = 51 m by (d) the rod and (e) a particle of charge -q = -4.46 fC that replaces the rod?Problem 14: Consider the semiarc of charge shown in the figure, that has an opening angle of θ0 = 35° and a charge density of λ = -23 μC/m. We are going to find the electric field at the point P, which is a constant distance R = 1.45 m from the semiarc. Use the coordinate system specified in the figure. Part (b) What is the x-component of the electric field at point P, in newtons per coulomb?
- Problem 4. Exponentially Decaying Charge Density. A spherically symmetric charge distribution is described by a volume charge density given by p = Poe-"/a, where po and a are both positive constants, and r is the distance from the center of the distribution. (a) Determine the electric field at any value of r. (b) Sketch the graph of the electric field magnitude with r. (c) Describe how the electric field varies with the distance r.In Figure 1, a non-conducting rod of length L = 10.0 cm has a charge –q = -3.0 fCuniformly distributed along its length.a) What is the linear charge density of the rod?b) What are the magnitude and direction of the electric field produced at point P, atdistance of a = 6.00 cm from the rod?c) What is the electric field magnitude produced at distance a=50m by the rod?A thin insulating rod is bent into a semicircular arc of radius a, and a total electric charge Q is distributed uniformly along the rod. Find an expression for the electric field at point p, the center of curvature of the arc. y
- A ring-shaped conductor with radius a = 2.30 cm has a total positive charge Q = 0.121 nC uniformly distributed around it. (electric field at point p which is in positive x-axis x= 35.0 cm) a) figure out the electric field very far away. Is it consistent with the coulombs law? b) figure out the electric field at the center of ring?Positive charge is distributed with a uniform linear density 1 along the positive x-axis from r to o, along the positive y-axis from r to o, and along a 90° arc of a circle of radius r, as shown below. Determine the direction and the magnitude of the net electric field due to this charge distribution at point O. Your final answer should be in terms of 2, r, and any necessary constants. + + + + + + + + + + + + + +A charge distribution creates the following electric field throughout all space: E(r, 0, q) = (3/r) (r hat) + 2 sin cos sin 0(theta hat) + sin cos p (phi hat). Given this electric field, calculate the charge density at location (r, 0, p) = (ab.c).