X(s)|X4+ (2.03 M) || Mn O4 1 minus (0.74 M)|Mn2+ (2.81 M)|H+ (2.24 M) The reduction potential for X4+ is 1.53 V. What is the potential of this non standard cell (in Volts)?   Given Equations: MnO4- + 4 H+ + 3 e → MnO2 + 2 H2O (E0 = 1.70 V) OR Mn O4 1 minus + 4 H+ + 3 electrons → Mn O2 + 2 H2O (E0 = 1.70 V) MnO4- + 8 H+ + 5 e → Mn2+ + 4 H2O (E0 = 1.51 V) OR Mn O4 1 minus + 8 H+ + 5 electrons → Mn1 2+ + 4 H2O (E0 = 1.51 V) E cell = E0cell - (0.0592/n) log Q

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