Example 1-16 (SI)The core in Figure 1-14 is made of cast iron. Find the coil MMF necessary to get a fluxof 15 x 10-4 Wb. Assume that the cross-sectional area for the core as well as the air gapis uniform and equals 20 x 10-4 m².PartCast ironAir gapTotal MMF0.08 mFigure 1-14 Core for Example 1-16.$15 x 10-415 × 10*Air GapSolutionThere are two parts to this circuit, the cast-iron core and the air gap (see Table 1-4).Table 1-4A20 x 10420 x 104B1,3 X 10-3 m0.750.75H4.5 × 10³5.97 x 10³0.05 m[0.261.3 x 10-³HI1170776.11946.1 Example 1-14 (SI)The core in Figure 1-12 has a uniform cross-sectional area of 9 x 10-4 m². To get a fluxof 0.75 x 10-³ Wb, find:(a) The coil MMF required(b) The current in the coilSolutionA systematic way to solve the problem is to set up Table 1-2. The table will have a rowfor each part of the circuit. In this example there are two parts; one made of cast iron,the other made of cast steel. The table is filled in from left to right as the calculationsare made.Cast IronIO500 TurnsTable 1-2PartCast ironCast steelTotal MMF2 cm-Figure 1-12 Core for Example 1-14.$0.75 X10-30.75 X 10-³A4 cm9 × 1049 x 104B0.830.83H9.4 k0.5 kCast Steel3 cm10.070.11HI65855713

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xample 1-16 (SI) The core in Figure 1-14 is made of cast iron. Find the coil MMF necessary to get a flux of 15 x 10-4 Wb. Assume that the cross-sectional area for the core as well as the air gap is uniform and equals 20 × 10-4 m². Part Cast iron Air gap Total MMF 0.08 m Figure 1-14 Core for Example 1-16. $ 15 x 10-4 15 x 10 Air Gap Solution There are two parts to this circuit, the cast-iron core and the air gap (see Table 1-4). Table 1-4 A 20 x 104 20 × 10 B 1,3 x 10-3 m 0.75 0.75 H 4.5 x 10¹ 5.97 x 105 0.05 m 1 0.26 1.3 × 10-³ HI 1170 776.1 1946.1

xample 1-16 (SI) The core in Figure 1-14 is made of cast iron. Find the coil MMF necessary to get a flux of 15 x 10-4 Wb. Assume that the cross-sectional area for the core as well as the air gap is uniform and equals 20 × 10-4 m². Part Cast iron Air gap Total MMF 0.08 m Figure 1-14 Core for Example 1-16. $ 15 x 10-4 15 x 10 Air Gap Solution There are two parts to this circuit, the cast-iron core and the air gap (see Table 1-4). Table 1-4 A 20 x 104 20 × 10 B 1,3 x 10-3 m 0.75 0.75 H 4.5 x 10¹ 5.97 x 105 0.05 m 1 0.26 1.3 × 10-³ HI 1170 776.1 1946.1

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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