x2 + 8x +3 10) y=- _ dy A) 3x2 + 8x - 3 dx X Find the derivative. A) 11) s= t3 tan t-√√t ds dt C) dy dx A) ds dt 12) y = 2+4 secx 5 A) y'=- C) y'= - A) 15) y = A) 2x+8 X dr de = t3 sec² t + 3t² tant + 5x In x x7 13) r 2004 cos 0 dr de t3 sec t tan t + 3t2 tan t-- = x² 5 x2 + 4 tan²x - 4 csc x =403 sin 0 - 04 cos 0 =403 sin 0 7lnx-1 x8 Find the derivative of y with respect to x, t, or 0, as appropriate. 14) y = In 5x 1 2√t B) - 1 2√t B) 1 5x 1-7lnx x8 B) B) dx B) dt dt B) y' = C) 2x + 8 2x3/2 3x2+ 8x3 2x3/2 = t3 sec² t + 3t2 tan t- D) y'=- dr de 3t2 sec² t- 22. 5 1 2√t - 4 sec x tan x 403 cos 0 + 04 sin 0 dr D) = 403 cos 0 - 04 sin 0 de 1-7lm x x14 +4 sec x tan x 1 2√t D) - 1 D) 1 +7ln x x14 10) 11) 12) 13) 14) 15)
x2 + 8x +3 10) y=- _ dy A) 3x2 + 8x - 3 dx X Find the derivative. A) 11) s= t3 tan t-√√t ds dt C) dy dx A) ds dt 12) y = 2+4 secx 5 A) y'=- C) y'= - A) 15) y = A) 2x+8 X dr de = t3 sec² t + 3t² tant + 5x In x x7 13) r 2004 cos 0 dr de t3 sec t tan t + 3t2 tan t-- = x² 5 x2 + 4 tan²x - 4 csc x =403 sin 0 - 04 cos 0 =403 sin 0 7lnx-1 x8 Find the derivative of y with respect to x, t, or 0, as appropriate. 14) y = In 5x 1 2√t B) - 1 2√t B) 1 5x 1-7lnx x8 B) B) dx B) dt dt B) y' = C) 2x + 8 2x3/2 3x2+ 8x3 2x3/2 = t3 sec² t + 3t2 tan t- D) y'=- dr de 3t2 sec² t- 22. 5 1 2√t - 4 sec x tan x 403 cos 0 + 04 sin 0 dr D) = 403 cos 0 - 04 sin 0 de 1-7lm x x14 +4 sec x tan x 1 2√t D) - 1 D) 1 +7ln x x14 10) 11) 12) 13) 14) 15)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
100%
Transcribed Image Text:x2 + 8x +3
10) y=-
_
dy
A) 3x2 + 8x - 3
dx
X
Find the derivative.
A)
11) s= t3 tan t-√√t
ds
dt
dy
dx
ds
dt
5
12) y = 2+4 secx
A) y'= -
A)
C) t3 sec t tan t + 3t2 tan t--
=
C) y'= -
A)
15) y =
2x+8
X
= t3 sec² t + 3t2 tan t +
A)
dr
de
5x
In x
x7
13) r 2004 cos 0
dr
de
5
x²
5
x2
+ 4 tan²x
- 4 csc x
403 sin 0 - 04 cos 0
=403 sin 0
7lnx-1
x8
Find the derivative of y with respect to x, t, or 0, as appropriate.
14) y = In 5x
1
2√t
B) -
1
2√t
B)
1
5x
1-7ln x
x8
B)
B)
dx
B)
dt
dt
B) y' =
C)
D) y'=-
dr
de
2x+8
2x3/2
3x2+ 8x3
2x3/2
= t3 sec² t + 3t2 tan t-
22.
5
C)=1/44
3t2 sec² t-
403 cos 0 + 04 sin 0
dr
D) = 403 cos 0 - 04 sin 0
de
1
2√t
-4 sec x tan x
1-7lm x
x14
+4 sec x tan x
1
2√√t
D) - 1
D)
1 +7ln x
x14
10)
11)
12)
13)
14)
15)
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