x²–1 Using a trigonometric substitution, the integral - dx becomes: Select one: [sec'e de tan*e O Ssin'e cose de O None Cose de sin*e (cos? e de sin“ e

Q: d dx A.sinh(Inx) B.–sinh(Inx) sinh(Inx) C.- X -cosh(x) D. X cosh (Inx) =

A:

Q: SHOW THAT : csc² (2 cot¯ /x -1 dx X - 1 Vx +x/x

A:

Q: sinx = 5/13, x E 5,1], then cosx =?

A: We are solving the problem by the property of trigonometry ratio.

Q: L, sin 8x cos 15x dx

A:

Q: 1 cotx ln sinx|dx x In [ x Ja 2 1 2

A: To find, ∫ cotx2lnsinx2dx Let I=∫ cotx2lnsinx2dx We know that cot(x2) = cos(x2)sin(x2). Therefore…

Q: 2- 1- 3一寸

A:

Q: Scos(cos2x) sin2x dx Given: Find: du О 2cos2x dx -2sin2x dx -2cos2x dx 2sin2x dx

A: The solution is given in the next step.

Q: Implitude for the function y = 6 cos(x)

A: The function is given as y=6cosx

Q: d (cos²> (cos? x.Tan x) at x=1 dx

A:

Q: cos x 4. Compute the integral 1+(sin x)? Hint: u-substitution

A: the given expression is: ∫0π2cosx1+sinx2dx let the given integral be I. therefore,…

Q: | cos (nt)sin(at) dt Find

A: This integral can be solved by the method of substitution.

Q: Srind dy /dx for X-(0)(cas20+ Osino andy

A:

Q: S sin cos do 30

A:

Q: sin (r) -dr. R nvoke to integrate even powe

A: An integral is given by, I = ∫Rsin2xx2dx. The objective is to evaluate and state the identities that…

Q: d (cot x) = dx A O sec? x .BO - CSC X cotx .C O sec x tan x D O - csc? x

A: Derivative of cot x

Q: Si cos°(3x)sin (3x) – cos (3x) sin°(3x) dx

A: First we common out cos7(3x) sin7(3x) and then apply the formula cos2(3x)-sin2(3x)=cos(6x)