X1 = (1 – K2)/(K1 – K2) x2 = 1- x yı = (K, K2 – Ki)/(K2- K1) y2 = 1- yı Vz(K – K2)/(1 – K2)] – 1 %3D %3D K1 -1 Table 4.4 Rachford-Rice Procedure for Isothermal-Flash Calculations When K-Values Are Independent of Composition ..., zc, Ty, Py Specified variables: F, TF, PF, Z1, 2, Steps (1) TL = Ty (2) PL = Py (3) Solve = È, z,(1 – K;) A1+ V(K; – 1) f{V} = E for V = V/F, where K; = K{Tv, Py}. (4) V = FY Zi (5) xi =: 1+ V(K - 1) Z;Ki (6) y; 1+ ¥(K; – 1) (7) L =F – V (8) Q = hyV+ hL – hFF

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Derivation of equilibrium-flash equations for a binary mixture.
For a binary mixture of components 1 and 2, show that the phase compositions and amounts can be computed directly from the following
reduced forms of Eqs. (5), (6), and (3) of Table 4.4:

X1 = (1 – K2)/(K1 – K2)
x2 = 1- x
yı = (K, K2 – Ki)/(K2- K1)
y2 = 1- yı
Vz(K – K2)/(1 – K2)] – 1
%3D
%3D
K1 -1
Transcribed Image Text:X1 = (1 – K2)/(K1 – K2) x2 = 1- x yı = (K, K2 – Ki)/(K2- K1) y2 = 1- yı Vz(K – K2)/(1 – K2)] – 1 %3D %3D K1 -1
Table 4.4 Rachford-Rice Procedure for Isothermal-Flash
Calculations When K-Values Are Independent of Composition
..., zc, Ty, Py
Specified variables: F, TF, PF, Z1, 2,
Steps
(1) TL = Ty
(2) PL = Py
(3) Solve
= È,
z,(1 – K;)
A1+ V(K; – 1)
f{V} = E
for V = V/F, where K; = K{Tv, Py}.
(4) V = FY
Zi
(5) xi =:
1+ V(K - 1)
Z;Ki
(6) y;
1+ ¥(K; – 1)
(7) L =F – V
(8) Q = hyV+ hL – hFF
Transcribed Image Text:Table 4.4 Rachford-Rice Procedure for Isothermal-Flash Calculations When K-Values Are Independent of Composition ..., zc, Ty, Py Specified variables: F, TF, PF, Z1, 2, Steps (1) TL = Ty (2) PL = Py (3) Solve = È, z,(1 – K;) A1+ V(K; – 1) f{V} = E for V = V/F, where K; = K{Tv, Py}. (4) V = FY Zi (5) xi =: 1+ V(K - 1) Z;Ki (6) y; 1+ ¥(K; – 1) (7) L =F – V (8) Q = hyV+ hL – hFF
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