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(x + y)dx + (2x - y)dy = (

(x + y)dx + (2x - y)dy = (

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the Homogeneous DE process then next is Separable DE, step by step.

(x + y)dx + (2x − y)dy = 0.
Transcribed Image Text:(x + y)dx + (2x − y)dy = 0.
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You transpose the (x+y)dx to the right, how come it didn't go negative?

Can you answer again? Use the Homogeneous DE process then next is Separable DE, step by step.

(x + y)dx + 2x - y dy = 0 2x - y dy= y|dy = (x + y)dx
Transcribed Image Text:(x + y)dx + 2x - y dy = 0 2x - y dy= y|dy = (x + y)dx
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