Use integration by parts twice to evaluate fet cos(3t)dt: Step 1: Let u = et and du + S fet cos(3t)dt = - = fet cos(3t)dt = cos(3t) dt. Apply integration by parts to get a result of the form dt. Step 2: Apply integration by parts once again, letting u = et and identifying du to get a result of the form 6t -K fet cos(3t)dt, where K = a positive number. The wrap up: Adding K fet cos(3t)dt to both sides of the equation, and dividing by (K + 1) yields the answer to the original question: fet cos(3t)dt = +C.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use integration by parts twice to evaluate fet cos(3t)dt:
Step 1: Let u = et and du
+S
fet cos(3t)dt =
-
=
fet cos(3t)dt =
cos(3t) dt. Apply integration by parts to get a result of the form
dt.
Step 2: Apply integration by parts once again, letting u = et and identifying du to get a result of the
form
6t
-K fet cos(3t)dt,
where K = a positive number.
The wrap up: Adding K fet cos(3t)dt to both sides of the equation, and dividing by (K + 1) yields
the answer to the original question:
fet cos(3t)dt = +C.
Transcribed Image Text:Use integration by parts twice to evaluate fet cos(3t)dt: Step 1: Let u = et and du +S fet cos(3t)dt = - = fet cos(3t)dt = cos(3t) dt. Apply integration by parts to get a result of the form dt. Step 2: Apply integration by parts once again, letting u = et and identifying du to get a result of the form 6t -K fet cos(3t)dt, where K = a positive number. The wrap up: Adding K fet cos(3t)dt to both sides of the equation, and dividing by (K + 1) yields the answer to the original question: fet cos(3t)dt = +C.
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