[√x x² + 6x dx In | (x + 3) + √(x + 3)² – 9 ) + – 3 (x+3)√(x+3)²-9 18 + 2/2 1m|| (x+3) + √(x+3)² - 9 -D))+ + C X

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hello, I am stuck on this trig integral. I am not sure where I am going wrong and I have attached my work. I apologies for the crammed work.

3ffrndide (2252019/09
(x+37²-9
55 da
45 Ja dx fuit du
u= x13
duzdr
THE LEA
/
u
35ce
de=3secoTonede
43TANG 350N) 9²-3√ √TA ²6
4 3TANG
9 SELETAN bile → af suce + see³6 de of seu + [swede] t
SE-
Hing who i
3
9 In/SECEPTANCI: + / SECOTANG + 2 secode]
=
Sv
29 [19/SECE + TANE / TE SECETANG + & In|SECETTANG)] +C
29
5 9 [ 1 / 3 + 1 + 2 ( 3 ) ( 23 ) + ( )=9] +9 [139 | + (x+3)/(0-32-5914-1 (+3) + (x+3)/- 19
3
18
M
ご
[¯¯¯J
Transcribed Image Text:3ffrndide (2252019/09 (x+37²-9 55 da 45 Ja dx fuit du u= x13 duzdr THE LEA / u 35ce de=3secoTonede 43TANG 350N) 9²-3√ √TA ²6 4 3TANG 9 SELETAN bile → af suce + see³6 de of seu + [swede] t SE- Hing who i 3 9 In/SECEPTANCI: + / SECOTANG + 2 secode] = Sv 29 [19/SECE + TANE / TE SECETANG + & In|SECETTANG)] +C 29 5 9 [ 1 / 3 + 1 + 2 ( 3 ) ( 23 ) + ( )=9] +9 [139 | + (x+3)/(0-32-5914-1 (+3) + (x+3)/- 19 3 18 M ご [¯¯¯J
Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.)
[v
9 In
x² + 6x dx
(x+3) + √(x+3)² - 9
+ 3)² – 9 -|)
3
+
(x+3) √ (x+3)² − 9
18
212 12 (1
+
²-))) + C
(x+3) + √(x+3)² − 9
3
Transcribed Image Text:Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) [v 9 In x² + 6x dx (x+3) + √(x+3)² - 9 + 3)² – 9 -|) 3 + (x+3) √ (x+3)² − 9 18 212 12 (1 + ²-))) + C (x+3) + √(x+3)² − 9 3
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