X-rays with a wavelength of 0.157 m are diffracted from the surface of a parallel set of planes in a crystal lattice at an angle of incidence of 50.98°. Assuming that the order of diffraction is n=2, what is the distance between the planes (in nm)? X-rays with a wavelength of 0.157 nm are diffracted from the surface of a parallel setof planes in a crystal lattice at an angle of incidence of 50.98°. Assuming that theorder of diffraction is n=2, what is the distance between the planes (in nm)?nλ = 2d sin(0)=Equation: nλYour Answer:

n = order of diffractiond = distance between the planes

Answered: X-rays with a wavelength of 0.157 nm…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter10: Liquids And Solids

Section: Chapter Questions

Problem 49E: X rays from a copper X-ray tube ( = 154 pm) were diffracted at an angle of 14.22 degrees by a...

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X-rays with a wavelength of 0.157 m are diffracted from the surface of a parallel set of planes in a crystal lattice at an angle of incidence of 50.98°. Assuming that the order of diffraction is n=2, what is the distance between the planes (in nm)?

X-rays with a wavelength of 0.157 nm are diffracted from the surface of a parallel set
of planes in a crystal lattice at an angle of incidence of 50.98°. Assuming that the
order of diffraction is n=2, what is the distance between the planes (in nm)?
nλ = 2d sin(0)
=
Equation: nλ
Your Answer:

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