01Xprocess service periodP1 729P21225P32 52fill in the gant chart below (until time 20) for the most feasible case (X, Y, or Z)3 4 56Yprocess service periodP1 8 34P23590P3 7207Zprocess service periodP15 2210P2 3P3 7 588 9 10 11 12 13 14151617181920

Given the 3 cases, X, Y and Z. The processes in the case can be scheduled if they satisfy the…

X process service period 29 P1 7 P2 12 25 P3 2 5 1 2 fill in the gant chart below (until time 20) for the most feasible case (X, Y, or Z) 3 4 Y process service period P1 8 34 P2 35 90 P3 7 20 5 6 7 Z process service period P1 5 22 P2 3 10 P3 7 58 8 9 10 11 12 13 14 15 16 17 18 19 20

X process service period 29 P1 7 P2 12 25 P3 2 5 1 2 fill in the gant chart below (until time 20) for the most feasible case (X, Y, or Z) 3 4 Y process service period P1 8 34 P2 35 90 P3 7 20 5 6 7 Z process service period P1 5 22 P2 3 10 P3 7 58 8 9 10 11 12 13 14 15 16 17 18 19 20

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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PRODUCTS P_CODE P DESCRIPT PRICE 123456 Flashlight 5.26 123457 Lamp 25.15 123458 Box Fan 10.99 213345 9v battery 1.92 254467 100W bulb 1.47 Dowerdill 2400 214459
A program in a computer is run with frequency of 40 MHz with 100,000 of instruction execution. The instruction type, instruction count and clock cycle per instruction is tabulated as in Table Q4 Table q4 Calculate it’s: (a) CPI (b) MIPS (c) Execution time
Coding problems: HW6_3 For a system of nine interconnected tanks (shown at right), the mass- balance equations are: ro1 Co1 + T41C4 ro2C02 + r12C1+r52C5 = (r12 + r15)C1 (r23 + r26)c2 T03C03 + 123C2 = r36C3 (r41 +r48 + r45)C4 T15C1 + T45C4 = (r52 + r58 + r59)C5 r04 C04 + 774C7 = r06 C06 + r26C2 + r36C3 = r69C6 ro7 C07 + r87 Cs = 174C7 ro8 Co8 + r58 C5 + T48C4 = (rs7 + rs9)Cs r'59C5 + r69C6 + T89C8 = rc9 The concentration of chemical inflow into tank T, is designated c, and the initial concentration in tank T, is designated Coi. The flow rate from tank Ti to Tj is designated rij. Furthermore, the total flow into each tank must equal the flow out, r (from tank 9). Given initial concentrations: Co1=1, Co2=2, Co3=1, coa=2, Co6=1, Co7=1 and Cos=1, in g/L given flow rate between tanks: r12=6, rıs=2, r23=5, r26=5, r36=8, ra1=5, ras=1, ras=1, rsz=1, rss=2, rs9=1, r69=15, r74=4, r37=2, ras=3, in L/min and given external flow rates (i.e., inflow into the tanks from outside): roz=3, ro2=3, ro3=3,…
13 P CODE 123456 123457 123458 213345 254467 311452 P_DESCRIPT Flashlight Lamp Box Fan 9v battery 100W bulb Powerdrill PRICE 1.3.2 Change the price of the Flashlight to 7.20 1.3.3 Delete Lamp from table PRODUCTS 1.3.4 Determine the cheapest product price 1.3.5 Determine the average price of all the products 25.15 10.99 1.92 1.47 34.99 Use an SQL command to do the following: 1.3.1 Insert a new row with the following data (P_CODE = 311234 P_DESCRIPT = hammerdril, PRICE = 8000)
10
A semiconductor manufacturer produces devices used as central processing units in personal computers. The speed of the devices (in megahertz) is important because it determines the price that the manufacturer can charge for the devices. The following table contains measurements on 120 devices. 680 669 719 699 670 710 677 669 700 718 690 681 702 696 692 649 675 701 721 683 735 688 763 672 681 722 663 658 634 720 690 679 691 683 705 746 706 649 668 717 727 683 652 720 660 695 701 724 668 698 668 660 653 637 660 693 679 682 704 652 664 702 661 720 695 670 656 723 710 680 684 705 681 662 644 683 695 678 674 724 748 697 690 656 667 683 698 672 642 694 660 659 704 690 724 680 739 704 695 718 660 648 703 660 722 691 680 685 681 715 665 676 665 675 655 659 720 675 697 663 This data set: Homework4, has been uploaded with our Homework#4 folder, download and read this data to R studio and use it to answer the following questions. a) Calculate the following using R, mean, median, standard…
The content of PC in the basic computer is 9AA (all mumbers are in hexadecimal). The coutent of AC is 7EA7. The content of memory at address 9AA is 933F. The content of memory at address 33F is 07AB. The content of memory at address 7AB is 8BBS. Table 1 Basic Computer Instructions Hexadesimal code Symbol Description 1-0 1-1 AND memory words to AC Add memory word to AC AND ADD Ixxx LDA Load memory word to AC Store content of AC in memory 2xxx Axxx STA BUN Branch unconditionally BSA Sxxx Dx Branch and save retum address ISZ Exxx Increment and skip if zero What is the instruction that will be fetched and executed next? O a. 9AB Ob.9AA +1 Oc 933F O d.a and b are correct Refer to Table 1 for the binary operation that will be performed in the AC when the instruction is executed and give its value. O a. OAAS b. 0ASC O. 7EAS O d. none of the above is correct Give the contents of registers PC, AR, DR, AC, and IR in hexadecimal at the end of the instruction cycle. Oa. PC -9AB, AR = 7AB, DR =…
what is the first stage of R(10) if using data Eneryption Standard second stage R10 = 111001011100101111011110100001110110111101010010 K11= 001110101000101100101111110100100011101111111101 Select one: a. 11011111 01000000 11110001 11110001 01010101 01010100 10111111 b. 11011111 01000000 11110001 11110001 01010101 01011010 10101111 c. 11011111 01000000 10000001 11110001 01010101 01010100 10101111 d. 11011111 01000000 11110001 11110001 01010101 01010100 10101001 e. 11011111 01000000 11110001 11110001 01010101 01010100 10101111
In an RISC V (32-bit) microprocessor, if a0 is preloaded with data of Ox0000_1F75 and al is preloaded with data of Ox0000_32CB, then what are the values of s0 (in Hex) after each of the following logical operations (in sequence)? xor s0, a0, al xori s0, s0, 0XFFFF slli s0, s0, 16
Plot the following in a line graph
A=[-1 -100;1 0];B=[1;0];C=[0 100];D=[0];[num,den]=ss2tf(A,B,C,D);sys=tf(num,den);step(sys); find the system response to step input 1- Delay time (td) 2- Rise time (tr) 3- Peak time (tp) 4- Maximum overshoot (Mp%)
Q5: 1800 lb 4 -1200 lb A truss is a structure made of members joined at their ends. For the truss shown in the figure, the forces in the nine members are determined by solv- ing the following system of nine equa- tions: MAX 48 S (2) 6 1 1500 lb F₂+ cos(48.81°)F₁ = 0 42 n 4211 48 ft F6+ cos(48.81°)F₁-F₂ = 0, sin (48.81°)F, +F3 = 0 -cos (48.81°)F₁+F₁ = 0 -sin (48.81°)F₁+F3 = 1800, -F- cos(48.81°)F, = 1200, -F₁-sin (48.81°)F,- sin(45°)F, = 0, sin (45°) F, = 1500, - cos(45°)F,-Fg = 0 Write the equations in matrix form and use MATLAB to determine the forces in the members. A positive force means tensile force and a negative force means compressive force. Display the results in a table where the first column displays the member number and the second column displays the correspond- ing force. The main concept of solving this problem depend on : Element-by-Element Operations The Transpose Operator Using Arrays in MATLAB Built-in Functions Solving Linear Equations All of the given