The couteut of PC in the basic computer is 9AA (all aumbers are in hexadecimal). The coutent of AC is 7EA7. The content of memory at address 9AA is 933F. The couteut of memory at address 33F is 07AB. The conteut of memory at address 7AB is 8885. Table 1 Basic Computer Instructions Hesadesimal sode 1-1 Symbol 1-0 Deseription AND memory words to AC Add memory word to AC Load memory word to AC Store content of AC in memory Branch unconditionaally AND ADD LDA Axx STA Bxxx BUN 4xxx CXx BSA Dxx Branch and save retum address ISZ Exxx Increment and skip if zero What is the instruction that will be fenched and executed next? Oa 9AB Ob.9AA +1 Oc 93F O da and b are correct Refer to Table 1 for the binary operation that will be performed in the AC when the instruction is executed and give its value. O a OAAS b.0ASC c. 7EAS d. none of the above is correct Give the contents of registers PC, AR, DR, AC, and IR in hexadecimal at the end of the instruction cyele. Oa PC - 9AB, AR-7AB, DR = 8BB5, AC -0ASC, IR = 933F Ob PC - 9AA, AR = 33F, DR - 07AB, AC = OA5C, IR = 933F OCPC-9AB, AR = 7AB, DR = 8BBS, AC 0AAS, IR = 7EA7 Od PC-9AA , AR-33F, DR-07AB, AC = 0AA5, IR = 933F %3D %3D %3D %3! %3D !!

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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The content of PC in the basic computer is 9AA (all mumbers are in hexadecimal). The coutent of AC is 7EA7. The content of memory at
address 9AA is 933F. The content of memory at address 33F is 07AB. The content of memory at address 7AB is 8BBS.
Table 1 Basic Computer Instructions
Hexadesimal code
Symbol
Description
1-0
1-1
AND memory words to AC
Add memory word to AC
AND
ADD
Ixxx
LDA
Load memory word to AC
Store content of AC in memory
2xxx
Axxx
STA
BUN
Branch unconditionally
BSA
Sxxx
Dx
Branch and save retum address
ISZ
Exxx
Increment and skip if zero
What is the instruction that will be fetched and executed next?
O a. 9AB
Ob.9AA +1
Oc 933F
O d.a and b are correct
Refer to Table 1 for the binary operation that will be performed in the AC when the instruction is executed and give its
value.
O a. OAAS
b. 0ASC
O. 7EAS
O d. none of the above is correct
Give the contents of registers PC, AR, DR, AC, and IR in hexadecimal at the end of the instruction cycle.
Oa. PC -9AB, AR = 7AB, DR = 8BB5, AC = 0ASC, IR = 933F
Ob. PC = 9AA, AR = 33F, DR = 07AB, AC = 0A5C, IR = 933F
OC PC = 9AB , AR = 7AB, DR = 8BB5, AC = 0AA5, IR = 7EA7
Od. PC = 9AA , AR = 33F, DR = 07AB, AC = 0AAS, IR = 933F
%3D
%3D
%3!
%3D
Transcribed Image Text:The content of PC in the basic computer is 9AA (all mumbers are in hexadecimal). The coutent of AC is 7EA7. The content of memory at address 9AA is 933F. The content of memory at address 33F is 07AB. The content of memory at address 7AB is 8BBS. Table 1 Basic Computer Instructions Hexadesimal code Symbol Description 1-0 1-1 AND memory words to AC Add memory word to AC AND ADD Ixxx LDA Load memory word to AC Store content of AC in memory 2xxx Axxx STA BUN Branch unconditionally BSA Sxxx Dx Branch and save retum address ISZ Exxx Increment and skip if zero What is the instruction that will be fetched and executed next? O a. 9AB Ob.9AA +1 Oc 933F O d.a and b are correct Refer to Table 1 for the binary operation that will be performed in the AC when the instruction is executed and give its value. O a. OAAS b. 0ASC O. 7EAS O d. none of the above is correct Give the contents of registers PC, AR, DR, AC, and IR in hexadecimal at the end of the instruction cycle. Oa. PC -9AB, AR = 7AB, DR = 8BB5, AC = 0ASC, IR = 933F Ob. PC = 9AA, AR = 33F, DR = 07AB, AC = 0A5C, IR = 933F OC PC = 9AB , AR = 7AB, DR = 8BB5, AC = 0AA5, IR = 7EA7 Od. PC = 9AA , AR = 33F, DR = 07AB, AC = 0AAS, IR = 933F %3D %3D %3! %3D
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