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X IIIIIII This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of finding the electron at point A, compares to Pg, the probability of finding the electron at point B. point A 100 pm below the nucleus along the -z axis. 100 pm to the left of the nucleus, along the -x axis. 100 pm in front of the nucleus, along the -y axis. point B 100 pm above the nucleus, along the +z axis. 100 pm behind the nucleus, along the +y axis. 100 pm to the right of the nucleus, along the +x axis. compare PA to PB OP P. A O PA P A Ps OPP A O PA= PB P> P. O A S ola Ar

X IIIIIII This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of finding the electron at point A, compares to Pg, the probability of finding the electron at point B. point A 100 pm below the nucleus along the -z axis. 100 pm to the left of the nucleus, along the -x axis. 100 pm in front of the nucleus, along the -y axis. point B 100 pm above the nucleus, along the +z axis. 100 pm behind the nucleus, along the +y axis. 100 pm to the right of the nucleus, along the +x axis. compare PA to PB OP P. A O PA P A Ps OPP A O PA= PB P> P. O A S ola Ar

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Here is a sketch of a 2p, orbital: Q Z 11 X This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how PA, the probability of finding the electron at point A, compares to Pg, the probability of finding the electron at point B. point A 100 pm below the nucleus along the -z axis. 100 pm to the left of the nucleus, along the -x axis. 100 pm in front of the nucleus, along the -y axis. point B 100 pm above the nucleus, along the +z axis. 100 pm behind the nucleus, along the +y axis. 100 pm to the right of the nucleus, along the +x axis. compare PA to PB O P<P. A B A B O P₁ = P₂ OPPB A O P₁ <PB OP=P O P > P X OP<P OP=P A O B P> P A Ś F ola Ar
Transcribed Image Text:Here is a sketch of a 2p, orbital: Q Z 11 X This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how PA, the probability of finding the electron at point A, compares to Pg, the probability of finding the electron at point B. point A 100 pm below the nucleus along the -z axis. 100 pm to the left of the nucleus, along the -x axis. 100 pm in front of the nucleus, along the -y axis. point B 100 pm above the nucleus, along the +z axis. 100 pm behind the nucleus, along the +y axis. 100 pm to the right of the nucleus, along the +x axis. compare PA to PB O P<P. A B A B O P₁ = P₂ OPPB A O P₁ <PB OP=P O P > P X OP<P OP=P A O B P> P A Ś F ola Ar
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