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x dx + (y - 2x)dy = 0

x dx + (y - 2x)dy = 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Can you check my ODE homogeneous solution if it is correct or not, thank you
x dx + (y - 2x)dy = 0
Transcribed Image Text:x dx + (y - 2x)dy = 0
x-y xdx + (y-2x) dy = 0 vy(vdy+ydv) + (y-2vy) dy vaydy+vyadv + yay-2vydy (√²-2√ +1)ydy + vy ² dv A V-1 V у ух dy + dv (√²-2√²+1) Sydy +f V.. QUED) [ ² A B + (V²-2V+1) (KT) N=12 Iny + n(V-1) = √/1-1 - V-I Iny + In (1-1) 4-1 *PRA - = с с Homo GENOUS ODE NO.: DATE: X=VY + U) (Z 5/8 прят пра=хр |^= ²/² | V = A(V-y) + B V₁:1 = A V₁₂:0=- A+B 12
Transcribed Image Text:x-y xdx + (y-2x) dy = 0 vy(vdy+ydv) + (y-2vy) dy vaydy+vyadv + yay-2vydy (√²-2√ +1)ydy + vy ² dv A V-1 V у ух dy + dv (√²-2√²+1) Sydy +f V.. QUED) [ ² A B + (V²-2V+1) (KT) N=12 Iny + n(V-1) = √/1-1 - V-I Iny + In (1-1) 4-1 *PRA - = с с Homo GENOUS ODE NO.: DATE: X=VY + U) (Z 5/8 прят пра=хр |^= ²/² | V = A(V-y) + B V₁:1 = A V₁₂:0=- A+B 12
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