ALTERNATE EXAMPLE (387)What z-score did I get?Analyzing the effect of transformations melPROBLEM:In a large introductory statistics class, the distribution of scores on a recent test follows anapproximately Normal distribution with a mean of 82.4 and a standard deviation of 5.1. LetX be the test score for a randomly selected student. To test the students' grasp of thematerial, the teacher cleverly decides to convert all the scores to z-scores and then reportthese values to students. If Z is the z-score for the randomly selected student, thenX -82.45.1(a) Find the mean of Z.(b) Calculate and interpret the standard deviation of Z.

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Answered: X-82.4 Z = 5.1 (a) Find the mean of Z.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called forced expiratory volume in one second, and is abbreviated FEV1. Assume the mean FEV1 for 10 -year-old boys is 2.1 liters and that the population standard deviation is =σ0.4 . A random sample of 35 10 -year-old boys who live in a community with high levels of ozone pollution are found to have a sample mean FEV1 of 1.98 liters. Can you conclude that the mean FEV1 in the high-pollution community differs from 2.1 liters? Use the =α0.10 level of significance and the P -value method with the TI-84 calculator. Part: 0 / 4 0 of 4 Parts Complete Part 1 of 4 State the appropriate null and alternate hypotheses. :H0 :H1 This hypothesis test is a ▼(Choose one) test.
Interpret the Z score for a student who scored an 91 on an exam that had a mean of 86 and a standard deviation of 5. One mean above the standard deviation One standard deviation above the mean One standard deviation below the mean One mean below the standard deviation
A population has mean u=30 and standard deviation o=7. (A) Find the z-score for a population value of 9. (B) Find the z-score for a population value of 51. (C) What number has a z-score of -2.3
Pulse rates of adult men are approximately normal with a mean of 70 and a standard deviation of 8. Which choice correctly describes how to find the proportion of men that have a pulse rate greater than 78? (a) Find the area to the right of z = -1 under a standard normal curve. (b) Find the area to the right of z=1 under a standard normal curve. (c) Find the area to the left of z = 1 under a standard normal curve. (d) Find the area between z=-1 and z=1 under a standard normal curve. (e) None of the above
Using a mean of 10 and standard deviation of 2.45, convert these z-scores back into raw scores. z-score = 1.11 Raw Score= _______________ z-score = -1 Raw Score= ______________ z-score= -0.92 Raw Score= _____________
Interval 30-39 40-49 50-59 60-69 70-79 80-89 90-99 Frequency 2 3 6. 4 11 31 33 Standard deviation = (Round to one decimal place as needed.) Consider a difference of 20% between two values of a standard deviation to be significant. How does this computed value compare with the given standard deviation, 11.1? O A. The computed value is not significantly different from the given value. B. The computed value is significantly greater than the given value. O c. The computed value is significantly less than the given value.
Now use the binomial formulas below to find the mean and standard deviation when n = 5 and p = 0.02.

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X-82.4 Z = 5.1 (a) Find the mean of Z. (b) Calculate and interpret the standard deviation of Z.