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X 4. The range of the function y = 2x? - 8x + 3 is 0/1 y > -5 y > -5 Option 1 Option 2 y > 3 y > 3 O Option 3 O Option 4

X 4. The range of the function y = 2x? - 8x + 3 is 0/1 y > -5 y > -5 Option 1 Option 2 y > 3 y > 3 O Option 3 O Option 4

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I don't get both the questions, how do I figure out the answers?

X 5. What is the range of the function y = -(x - p)² + q? 0/1 Y <p Option 1 Option 2 O Option 3 Option 4
Transcribed Image Text:X 5. What is the range of the function y = -(x - p)² + q? 0/1 Y <p Option 1 Option 2 O Option 3 Option 4
X 4. The range of the function y = 2x? - 8x + 3 is 0/1 y > -5 y > -5 Option 1 Option 2 y > 3 y > 3 O Option 3 Option 4
Transcribed Image Text:X 4. The range of the function y = 2x? - 8x + 3 is 0/1 y > -5 y > -5 Option 1 Option 2 y > 3 y > 3 O Option 3 Option 4
Expert Solution
Step 1

When the quadratic functions are in standard form,y=ax2+bx+c

If a is positive, the function opens up; if it’s negative, then function opens down.

In this form, then y-coordinate of the vertex is found by evaluating f(-b2a).

 

When quadratic equations are in vertex form, f(x)=a(x−h)2+k

As with standard form, if a is positive, then function opens up; if it’s negative, then function opens down.

The vertex is given by the coordinates (h, k), so all we need to consider is the k.

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