X -2 -1 TOHN 3 0 1 2 y 14 -1 -6 -1 14 39
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Write the equation for question 9 showing all your work.
Expert Solution
Step 1
The equation is y=a+bx+cx2 and the normal equations are
∑y=an+b∑x+c∑x2
∑xy=a∑x+b∑x2+c∑x3
∑x2y=a∑x2+b∑x3+c∑x4
The values are calculated using the following table
x | y | x2 | x3 | x4 | x⋅y | x2⋅y |
-2 | 14 | 4 | -8 | 16 | -28 | 56 |
-1 | -1 | 1 | -1 | 1 | 1 | -1 |
0 | -6 | 0 | 0 | 0 | 0 | 0 |
1 | -1 | 1 | 1 | 1 | -1 | -1 |
2 | 14 | 4 | 8 | 16 | 28 | 56 |
3 | 39 | 9 | 27 | 81 | 117 | 351 |
--- | --- | --- | --- | --- | --- | --- |
∑x=3 | ∑y=59 | ∑x2=19 | ∑x3=27 | ∑x4=115 | ∑x⋅y=117 | ∑x2⋅y=461 |
Substituting these values in the normal equations
6a+3b+19c=59
3a+19b+27c=117
19a+27b+115c=461
Solving these 3 equations,
Total Equations are 3
6a+3b+19c=59→(1)
3a+19b+27c=117→(2)
19a+27b+115c=461→(3)
Select the equations (1) and (2), and eliminate the variable a.
6a+3b+19c=59 | ×1→ | 6a | + | 3b | + | 19c | = | 59 | |||
− | |||||||||||
3a+19b+27c=117 | ×2→ | 6a | + | 38b | + | 54c | = | 234 | |||
- | 35b | - | 35c | = | -175 | →(4) |
Select the equations (2) and (3), and eliminate the variable a.
3a+19b+27c=117 | ×19→ | 57a | + | 361b | + | 513c | = | 2223 | |||
− | |||||||||||
19a+27b+115c=461 | ×3→ | 57a | + | 81b | + | 345c | = | 1383 | |||
280b | + | 168c | = | 840 | →(5) |
Select the equations (4) and (5), and eliminate the variable c.
-35b-35c=-175 | ×24→ | - | 840b | - | 840c | = | -4200 | ||||
+ | |||||||||||
280b+168c=840 | ×5→ | 1400b | + | 840c | = | 4200 | |||||
560b | = | 0 | →(6) |
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