X -2 -1 TOHN 3 0 1 2 y 14 -1 -6 -1 14 39

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Write the equation for question 9 showing all your work.

This image contains a data table with two columns labeled "x" and "y". Below is the transcribed content:

| x  | y  |
|----|----|
| -2 | 14 |
| -1 | -1 |
| 0  | -6 |
| 1  | -1 |
| 2  | 14 |
| 3  | 39 |

The table shows pairs of values where the variable "x" is an integer, and the corresponding "y" value varies across the row. This table could be used to observe the relationship between "x" and "y" for educational purposes, such as interpreting data trends or exploring mathematical functions.
Transcribed Image Text:This image contains a data table with two columns labeled "x" and "y". Below is the transcribed content: | x | y | |----|----| | -2 | 14 | | -1 | -1 | | 0 | -6 | | 1 | -1 | | 2 | 14 | | 3 | 39 | The table shows pairs of values where the variable "x" is an integer, and the corresponding "y" value varies across the row. This table could be used to observe the relationship between "x" and "y" for educational purposes, such as interpreting data trends or exploring mathematical functions.
Expert Solution
Step 1

The equation is y=a+bx+cx2 and the normal equations are

y=an+bx+cx2

xy=ax+bx2+cx3

x2y=ax2+bx3+cx4


The values are calculated using the following table

x y x2 x3 x4 xy x2y
-2 14 4 -8 16 -28 56
-1 -1 1 -1 1 1 -1
0 -6 0 0 0 0 0
1 -1 1 1 1 -1 -1
2 14 4 8 16 28 56
3 39 9 27 81 117 351
--- --- --- --- --- --- ---
x=3 y=59 x2=19 x3=27 x4=115 xy=117 x2y=461



Substituting these values in the normal equations
6a+3b+19c=59

3a+19b+27c=117

19a+27b+115c=461


Solving these 3 equations,
Total Equations are 3

6a+3b+19c=59(1)

3a+19b+27c=117(2)

19a+27b+115c=461(3)



Select the equations (1) and (2), and eliminate the variable a.

6a+3b+19c=59 ×1     6a + 3b + 19c = 59  
     
3a+19b+27c=117 ×2     6a + 38b + 54c = 234  
     
          - 35b - 35c = -175 (4)





Select the equations (2) and (3), and eliminate the variable a.

3a+19b+27c=117 ×19     57a + 361b + 513c = 2223  
     
19a+27b+115c=461 ×3     57a + 81b + 345c = 1383  
     
            280b + 168c = 840 (5)





Select the equations (4) and (5), and eliminate the variable c.

-35b-35c=-175 ×24       - 840b - 840c = -4200  
    +  
280b+168c=840 ×5         1400b + 840c = 4200  
     
            560b     = 0 (6)
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