X 0 1 Y(X = 3) 3K 2K A random variable X has the following probability distribution 22 3 K 4K Then P(X≥2)= a) 0.1 b) 0.2 c) 0.4 d) 0.5

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 9E
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X
0
1
Y(X = 3)
3K
2K
A random variable X has the following probability distribution
22
3
K
4K
Then P(X≥2)=
a) 0.1
b) 0.2
c) 0.4
d) 0.5
Transcribed Image Text:X 0 1 Y(X = 3) 3K 2K A random variable X has the following probability distribution 22 3 K 4K Then P(X≥2)= a) 0.1 b) 0.2 c) 0.4 d) 0.5
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