Brian is in charge of the mailroom of the Boryk Corporation. Each day the company receivesseveral packages via the U.S. Postal system, for which he must sign. The following is theprobability distribution for the number of daily pieces of mail that comes via the Postal system. 10X2345 6 78P(x) | 0.02 0.03 0.25 0.19 0.16 0.14 0.12 0.08 0.01Find the mean of this distribution

Answered: Image /qna-images/answer/e4e8d05f-1c3e-4ebd-b10c-70e6c6c63a4c.jpg

Answered: X 0 1 2 3 4 8 5 6 7 P(x) | 0.02 0.03…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Below is a graph of a normal distribution with mean μ = -5 and standard deviation = 3. The shaded region represents the probability of obtaining a value from this distribution that is greater than -2. 0.4 103+ 0.2+ 04- Shade the corresponding region under the standard normal curve below. 0.1+ 034 0.2+ 0.1+ X
A normal distribution problem
X values: 2, 1, 6, 1, 1, 1 For each X, compute a deviation from the mean and place those deviations on the graph of X (histogram sketch of bell-shaped distribution) with mean labeled.
F-H please
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view Standard Normal Table (Page 1) - A 0.55 The indicate NEGATIVE Z Scores -3.50 Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 -.02 .03 .04 .05 .06 .07 .08 .09 and lower .0001 -3.4 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0002 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 .0004 .0004 .0004 .0003 -3.2 0007 .0007 .0006 .0006 .0006 .0006 .0006 .0005 .0005 .0005 -31 0010 .0009 .0009 .0009 .0008 .0008 .0008 .0008 .0007 .0007 -3.0 .0013 0013 .0013 .0012 .0012 .0011 .0011 .0011 0010 .0010 -2.9 .0019 0018 0018 .0017 0016 .0016 .0015 .0015 .0014 .0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 .0021 .0020 .0019 -2.7 .0035 .0034 .0033 .0032 .0031 .0030 0029 .0028 .0027 .0026 -2.6 .0047 .0045 0044 .0043 .0041 .0040 .0039 .0038 .0037 .0036 -2.5 .0062 .0060 .0059 .0057 .0055…
10 x P(x) 0 0.169 1 0.363 2 0.306 3 0.128 4 0.033 5 0.001
Below is a graph of a normal distribution with mean µ= − 1 and standard deviation σ=3. The shaded region represents the probability of obtaining a value from this distribution that is greater than - 4. + -7 -6 -5 4 -4 Shade the corresponding region under the standard normal curve below. -3 -2 1 -1 0.4 0.3+ 0.2+ 0.1- 0.47 0.3+ 0.2+ 0.1+ 1 2 3 4 5 + 6 7 X S
the mean is 146, and standard deviation is 35. A score of 181 is how many z-scores above the mean?
-3 -2 -1 1 2 3 Please show your answer to 2 decimal places. About % of the area under the curve of the standard normal distribution (u O and o = 1) is outside the interval Z = (-1.44,1.44) (or beyond 1.44 standard deviations of the mean).
x: 4 5 6 p(x): 0.25 0.6 0.15 x 4 5 6 p(x) 0.25 0.6 0.15 I know the mean is 4.9 for the above distribution. What is the standard deviation?
Below is a graph of a normal distribution with mean u=-3 and standard deviation o=2. The shaded region represents the probability of obtaining a value from this distribution that is greater than -4. 0.4 0.3+ 0.2+ 0.4+ Shade the corresponding region under the standard normal curve below. 0.1+ 0.3+ 0.2+ 0.1+ X
Below is a graph of a normal distribution with mean μ--3 and standard deviation o=2. The shaded region represents the probability of obtaining a value from this distribution that is greater than -5. -4 -3 -2 Shade the corresponding region under the standard normal curve below. -1 0.4- 0.3- 0.2+ 0.4+ 0.1+ 0.3- 0.2+ 0.1+ 2 3 4 N 5

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X 0 1 2 3 4 8 5 6 7 P(x) | 0.02 0.03 0.25 0.19 0.16 0.14 0.12 0.08 0.01 Find the mean of this distribution