*** he average diameter of sand dollars on a certain eland is 5.00 centimeters with a standarddeviation of 0.60 centimeters, If 25 sand dellars are chosen at random for a collection, findhe probability that the average diameter of those sand dollars is between 4.55 and 4.88centimeters. Assume that the variable is normally distributed.(a) .6587 (b) .0436 (c).1586 (d).3413 (e).8413

Answered: Image /qna-images/answer/6aa06c3b-1878-48f9-86ea-8e148c6420be.jpg

ne average diameter of sand dollars on a sertain island is 5.00 centimeters with a standard deviation of0.60 centimeters, If 25 sand dollars are chosen at random for a collection, find the probability that the average diameter of those sand dollars is between 4.55 and 4.88 centimeters. Assume that the variable is normally distributed. (a) .6587 (b) .0436 (e).1586 (d) .3413 (e).8413

ne average diameter of sand dollars on a sertain island is 5.00 centimeters with a standard deviation of0.60 centimeters, If 25 sand dollars are chosen at random for a collection, find the probability that the average diameter of those sand dollars is between 4.55 and 4.88 centimeters. Assume that the variable is normally distributed. (a) .6587 (b) .0436 (e).1586 (d) .3413 (e).8413

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Assume that the readings on the thermometers are normally distributed with a mean of 0° and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. Find the probability of each reading in degrees. (a) Between 0 and 1.48: (b) Between -1.84 and 0: (c) Between –0.0299999999999998 and 2.06: (d) Less than -0.23: (e) Greater than -0.11:
Assume that females have pulse rates that are normally distributed with a mean of μ = 74.0 beats per minute and a standard deviation of o= 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is between 70 beats per minute and 78 beats per minute. The probability is. (Round to four decimal places as needed.) b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean between 70 beats per minute and 78 beats per minute. The probability is (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? A. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. B. Since the mean pulse rate exceeds 30, the distribution of sample means is a normal distribution for any sample size. C. Since the…
This is for statistics and probability
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of O'C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P79, the 79-percentile. This is the temperature reading separating the bottom 79% from the top 21%. P79
Today, the waves are crashing onto the beach every 5.6 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.6 seconds. Round to 4 decimal places where possible. a. The mean of this distribution is b. The standard deviation is c. The probability that wave will crash onto the beach exactly 0.7 seconds after the person arrives is P(x = 0.7) = d. The probability that the wave will crash the beach between 1.6 and 5.1 seconds after the person arrives is P(1.6 3.72) = f. Suppose that the person has already been standing at the shoreline for 0.8 seconds without a wave crashing in. Find the probability that it will take between 1.4 and 3.3 seconds for the wave to crash onto the shoreline. g. 65% of the time a person will wait at least how long before the wave crashes in? seconds. h. Find the minimum for the upper quartile. seconds.
J 1
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0beats per minute and a standard deviation of σ=12.5 beats per minute. a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 79beats per minute. The probability is _____.(Round to four decimal places as needed.) b. If 16 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 79beats per minute. The probability is ____. (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? A. Since the distribution is of sample means, not individuals, the distribution is a normal distribution for any sample size. B. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size. C. Since the mean pulse rate exceeds 30, the…
Assume that thermometer readings are normally distributed with a mean of 0 degreesC and a standard deviation of 1.00degreesC. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 0.50 and 2.00
The age of children in kindergarten on the first day of school is uniformly distributed between 4.91 and 5.97 years old. A first time kindergarten child is selected at random. Round answers to 4 decimal places if possible. a. The mean of this distribution is b. The standard deviation is c. The probability that the the child will be older than 5 years old?
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Let Z represent the reading of this thermometer at freezing. What reading separates the highest 46.73% from the rest? That is, if P(z > c) = 0.4673, find c. c = °C
Suppose that the weight of an newborn fawn is Uniformly distributed between 2.2 and 3.8 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. The mean of this distribution is The standard deviation is The probability that fawn will weigh exactly 2.4 kg is P(x = 2.4) = The probability that a newborn fawn will be weigh between 2.9 and 3.7 is P(2.9 < x < 3.7) = The probability that a newborn fawn will be weigh more than 2.72 is P(x > 2.72) = P(x > 2.8 | x < 3.5) = Find the 25th percentile.
Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of μ = 1.1 kg and a standard deviation of a=4.9 kg Complete parts (a) through (c) below. CODE a. If 1 male college student is randomly selected, find the probability that he gains between 0 kg and 3 kg during freshman year. The probability is 2388 (Round to four decimal places as needed.) b. If 16 male college students are randomly selected, find the probability that their mean weight gain during freshman year is between 0 kg and 3 kg The probability is 8663 (Round to four decimal places as needed.)