Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question
![Welcome to our educational website! Today, we'll analyze a geometry problem involving triangle congruence.
**Problem Statement:**
We have the following geometric figure, which includes triangle XYZ with a point W on line segment XZ such that WZ passes through to point Y, creating two smaller triangles: ΔXWZ and ΔYWZ.
Based on the provided conditions:
1. Line segment \( \overline{WZ} \) bisects \( \angle XZY \)
2. \( \angle X \cong \angle Y \)
We are asked which method of triangle congruence can be used to prove that \( \triangle XWZ \cong \triangle YWZ \).
**Options:**
- SSS (Side-Side-Side)
- AAA (Angle-Angle-Angle)
- SAS (Side-Angle-Side)
- AAS (Angle-Angle-Side)
**Detailed Explanation of the Diagram:**
- The diagram consists of a large triangle \( \triangle XZY \) with a line segment \( \overline{WZ} \) drawn from point \( W \) on side \( \overline{XZ} \) to point \( Z \) and extended to point \( Y \), forming two smaller triangles: ΔXWZ and ΔYWZ.
- \( \overline{WZ} \) is a common side of both triangles ΔXWZ and ΔYWZ.
Given these conditions, the method to prove the congruence can be identified as follows:
1. \( \overline{WZ} \) is a common side for both triangles.
2. \( \angle X \cong \angle Y \) means that the angles at points X and Y are equal.
3. Since \( \overline{WZ} \) bisects \( \angle XZY \), the two resulting angles \( \angle XWZ \) and \( \angle YWZ \) are equal.
Therefore, we have:
- An angle (\( \angle X \cong \angle Y \))
- A side (\( \overline{WZ} \) common)
- An angle (\( \angle XWZ \cong \angle YWZ \))
This corresponds to the Angle-Angle-Side (AAS) method of proving triangle congruence.
**Correct Answer:**
- AAS](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6f766445-6e88-4449-9b12-3a9b363ebf4d%2F993c3a16-43ca-41ab-80df-c40b212f0106%2Fugar7v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Welcome to our educational website! Today, we'll analyze a geometry problem involving triangle congruence.
**Problem Statement:**
We have the following geometric figure, which includes triangle XYZ with a point W on line segment XZ such that WZ passes through to point Y, creating two smaller triangles: ΔXWZ and ΔYWZ.
Based on the provided conditions:
1. Line segment \( \overline{WZ} \) bisects \( \angle XZY \)
2. \( \angle X \cong \angle Y \)
We are asked which method of triangle congruence can be used to prove that \( \triangle XWZ \cong \triangle YWZ \).
**Options:**
- SSS (Side-Side-Side)
- AAA (Angle-Angle-Angle)
- SAS (Side-Angle-Side)
- AAS (Angle-Angle-Side)
**Detailed Explanation of the Diagram:**
- The diagram consists of a large triangle \( \triangle XZY \) with a line segment \( \overline{WZ} \) drawn from point \( W \) on side \( \overline{XZ} \) to point \( Z \) and extended to point \( Y \), forming two smaller triangles: ΔXWZ and ΔYWZ.
- \( \overline{WZ} \) is a common side of both triangles ΔXWZ and ΔYWZ.
Given these conditions, the method to prove the congruence can be identified as follows:
1. \( \overline{WZ} \) is a common side for both triangles.
2. \( \angle X \cong \angle Y \) means that the angles at points X and Y are equal.
3. Since \( \overline{WZ} \) bisects \( \angle XZY \), the two resulting angles \( \angle XWZ \) and \( \angle YWZ \) are equal.
Therefore, we have:
- An angle (\( \angle X \cong \angle Y \))
- A side (\( \overline{WZ} \) common)
- An angle (\( \angle XWZ \cong \angle YWZ \))
This corresponds to the Angle-Angle-Side (AAS) method of proving triangle congruence.
**Correct Answer:**
- AAS
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