Write the rate law for the following elementary reaction: 2 NO(g) + O₂(g) → 2 NO₂(g) Use k₁ to stand for the rate constant. rate =

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Chapter1: Chemical Foundations
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Write the rate law for the following elementary reaction:
2 NO(g) + O₂(g) → 2 NO₂(g)
Use k, to stand for the rate constant.
rate = 0
0/0
X
ㅁ
G
믐
Transcribed Image Text:Tags: Goal Topic Tags: Goal Topic, Locked Write the rate law for the following elementary reaction: 2 NO(g) + O₂(g) → 2 NO₂(g) Use k, to stand for the rate constant. rate = 0 0/0 X ㅁ G 믐
Expert Solution
Step 1

Rate law :- 

The rate of reaction is directly proportional to molar concentration of reactant raised to simple power.

The experimentallly determined equation that expresses the rate of a chemical reaction in terms of molar concentration of reactants raised to simple power is called as rate law. 

Consider, a reaction  aA + bB  cC 

The rate of above is given by 

        rate α [A]x[B]y 

i.e.   rate = k [A]x[B]y 

proportionality constant called rate constant. 

Note that, 'x' and 'y' are experimentallly determined quantities and may or may not be equal to 'a' and 'b' 

-------------------------------- 

Elementary reaction :- 

The reaction which take place in single step and cannot be broken down further into any simpler chemical reaction is called Elementary reaction. 

-------------------------------- 

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