Write the pseudocode for an application that will request the user to enter the radius of a circle. The radius is the measurement from the centre of the circle to the edge of the circle. The radius should then be passed to a method which will use the value of the radius to compute the area of a circle. The result of the calculation should be returned to the mainline logic which should display the area of the circle. The formula for calculating the area of a circle is: radius- dius

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Write the pseudocode for an application that will request the user to enter the radius of a circle.
The radius is the measurement from the centre of the circle to the edge of the circle. The radius
should then be passed to a method which will use the value of the radius to compute the area of a
circle. The result of the calculation should be returned to the mainline logic which should display
the area of the circle. The formula for calculating the area of a circle is:
Of
radius
-area
A = π xr²
The calculation can also be written as: A = 3.14 x (rxr)
r = radius
A = area
π = 3.14 (which is called Pl)
Note: Provide appropriate comments in your pseudocode.
Transcribed Image Text:Write the pseudocode for an application that will request the user to enter the radius of a circle. The radius is the measurement from the centre of the circle to the edge of the circle. The radius should then be passed to a method which will use the value of the radius to compute the area of a circle. The result of the calculation should be returned to the mainline logic which should display the area of the circle. The formula for calculating the area of a circle is: Of radius -area A = π xr² The calculation can also be written as: A = 3.14 x (rxr) r = radius A = area π = 3.14 (which is called Pl) Note: Provide appropriate comments in your pseudocode.
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