I need help. **Question:**Write the product as a sum:\[ 18 \cos(35u) \cos(12u) = \]---**Solution:**To express the product as a sum, use the trigonometric identity for the product-to-sum formula for cosine:\[\cos A \cos B = \frac{1}{2} [\cos (A + B) + \cos (A - B)]\]Given:\[A = 35u, \quad B = 12u\]Substitute into the formula:\[\cos(35u) \cos(12u) = \frac{1}{2} [\cos(35u + 12u) + \cos(35u - 12u)]\]\[= \frac{1}{2} [\cos(47u) + \cos(23u)]\]Therefore:\[18 \cos(35u) \cos(12u) = 18 \times \frac{1}{2} [\cos(47u) + \cos(23u)]\]\[= 9[\cos(47u) + \cos(23u)]\]Final result:\[18 \cos(35u) \cos(12u) = 9 \cos(47u) + 9 \cos(23u)\]

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Calculus: Early Transcendentals

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Chapter1: Functions And Models

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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Write the product as a sum: 18 cos(35u) cos(12u)