**Title: Understanding Precipitation Reactions - Net Ionic Equations****Text:**Write the net ionic equation for this precipitation reaction. Include physical states.\[\text{(NH}_4\text{)}_2\text{CO}_3\text{(aq) + Ca(ClO}_4\text{)}_2\text{(aq) → CaCO}_3\text{(s) + 2NH}_4\text{ClO}_4\text{(aq)}\]**Explanation:**In this chemical reaction, aqueous solutions of ammonium carbonate \((\text{NH}_4\text{)}_2\text{CO}_3\) and calcium perchlorate \(\text{Ca(ClO}_4\text{)}_2\) react to form solid calcium carbonate \(\text{CaCO}_3\) and aqueous ammonium perchlorate \(\text{2NH}_4\text{ClO}_4\). The precipitation of calcium carbonate is the primary focus, as it forms a solid, while the other compound remains dissolved in the solution.

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Answered: Write the net ionic equation for this…

Write the net ionic equation for this precipitation reaction. Include physical states. (NH₁)₂CO³(aq) + Ca(ClO³)₂(aq) — CaCO3(s) + 2 NHÃCIO(aq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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**Title: Understanding Precipitation Reactions - Net Ionic Equations**

**Text:**
Write the net ionic equation for this precipitation reaction. Include physical states.

\[
\text{(NH}_4\text{)}_2\text{CO}_3\text{(aq) + Ca(ClO}_4\text{)}_2\text{(aq) → CaCO}_3\text{(s) + 2NH}_4\text{ClO}_4\text{(aq)}
\]

**Explanation:**
In this chemical reaction, aqueous solutions of ammonium carbonate \((\text{NH}_4\text{)}_2\text{CO}_3\) and calcium perchlorate \(\text{Ca(ClO}_4\text{)}_2\) react to form solid calcium carbonate \(\text{CaCO}_3\) and aqueous ammonium perchlorate \(\text{2NH}_4\text{ClO}_4\). The precipitation of calcium carbonate is the primary focus, as it forms a solid, while the other compound remains dissolved in the solution.

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