Write the net ionic equation for the following molecular equation. 2Fel3(aq) + 3(NH)½CO3(aq) –→Fe(CO3)3(s) + 6NH4I(aq) +

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### Educational Resource on Writing Net Ionic Equations

This section is designed to aid students in understanding how to write net ionic equations from given molecular equations. Follow the step-by-step instructions and make sure to specify the states of compounds as aqueous (aq) or solid (s), if applicable. If a box is not needed, leave it blank.

#### Example Problem:

**Given Molecular Equation:**
\[ 2FeI_3(aq) + 3(NH_4)_2CO_3(aq) \rightarrow Fe_2(CO_3)_3(s) + 6NH_4I(aq) \]

**Task:**
Write the net ionic equation for the reaction above.

**Steps:**

1. **Write the Full Ionic Equation:**
   - First, split all aqueous compounds into their respective ions.
   - \( 2FeI_3(aq) \) dissociates into \( 2Fe^{3+}(aq) + 6I^-(aq) \).
   - \( 3(NH_4)_2CO_3(aq) \) dissociates into \( 6NH_4^+(aq) + 3CO_3^{2-}(aq) \).
   
   Full ionic equation:
   \[ 2Fe^{3+}(aq) + 6I^-(aq) + 6NH_4^+(aq) + 3CO_3^{2-}(aq) \rightarrow Fe_2(CO_3)_3(s) + 6NH_4^+(aq) + 6I^-(aq) \]

2. **Identify and Cancel Spectator Ions:**
   - Spectator ions are ions that appear on both sides of the equation in the same form.
   - The spectator ions in this equation are \( 6NH_4^+(aq) \) and \( 6I^-(aq) \).

3. **Write the Net Ionic Equation:**
   - Removing the spectator ions leaves:
     \[ 2Fe^{3+}(aq) + 3CO_3^{2-}(aq) \rightarrow Fe_2(CO_3)_3(s) \]

**Answer Summary:**

- **Reactants:** \( 2Fe^{3+}(aq) + 3CO_3^{2-}(aq) \)
- **Products:** \( Fe_2
Transcribed Image Text:--- ### Educational Resource on Writing Net Ionic Equations This section is designed to aid students in understanding how to write net ionic equations from given molecular equations. Follow the step-by-step instructions and make sure to specify the states of compounds as aqueous (aq) or solid (s), if applicable. If a box is not needed, leave it blank. #### Example Problem: **Given Molecular Equation:** \[ 2FeI_3(aq) + 3(NH_4)_2CO_3(aq) \rightarrow Fe_2(CO_3)_3(s) + 6NH_4I(aq) \] **Task:** Write the net ionic equation for the reaction above. **Steps:** 1. **Write the Full Ionic Equation:** - First, split all aqueous compounds into their respective ions. - \( 2FeI_3(aq) \) dissociates into \( 2Fe^{3+}(aq) + 6I^-(aq) \). - \( 3(NH_4)_2CO_3(aq) \) dissociates into \( 6NH_4^+(aq) + 3CO_3^{2-}(aq) \). Full ionic equation: \[ 2Fe^{3+}(aq) + 6I^-(aq) + 6NH_4^+(aq) + 3CO_3^{2-}(aq) \rightarrow Fe_2(CO_3)_3(s) + 6NH_4^+(aq) + 6I^-(aq) \] 2. **Identify and Cancel Spectator Ions:** - Spectator ions are ions that appear on both sides of the equation in the same form. - The spectator ions in this equation are \( 6NH_4^+(aq) \) and \( 6I^-(aq) \). 3. **Write the Net Ionic Equation:** - Removing the spectator ions leaves: \[ 2Fe^{3+}(aq) + 3CO_3^{2-}(aq) \rightarrow Fe_2(CO_3)_3(s) \] **Answer Summary:** - **Reactants:** \( 2Fe^{3+}(aq) + 3CO_3^{2-}(aq) \) - **Products:** \( Fe_2
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