Write the Keq expression and Keq value 2N,O5 (3) == O2 (2) + 4NO2(2) Keq =144 at 200 ° C. O2 ) + 4NO2 ) == 2N,O5 («) a. 2NO2 (2) b. ½ O2 (2) + 2NO26) == N½O5 (2) c. N,O5 (2) d. 202) + 8NO2 ) 2O2 + 2NO2 () == 4N,O5 (g) с. e N2O5 == ¼ O2 (2) + NO2 (2) (3) e.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Problem 1.1P
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May I know the answer of letter d. and e.

Write the Keq expression and Keq
value
2N,O5 (3)
== O2 (2) + 4NO2(2) Keq =144 at 200 ° C.
O2 )
+ 4NO2 ) == 2N,O5 («)
a.
2NO2 (2)
b. ½ O2 (2) + 2NO26) == N½O5 (2)
c. N,O5 (2)
d. 202) + 8NO2 )
2O2 + 2NO2 ()
== 4N,O5 (g)
с.
e N2O5
== ¼ O2 (2) + NO2 (2)
(3)
e.
Transcribed Image Text:Write the Keq expression and Keq value 2N,O5 (3) == O2 (2) + 4NO2(2) Keq =144 at 200 ° C. O2 ) + 4NO2 ) == 2N,O5 («) a. 2NO2 (2) b. ½ O2 (2) + 2NO26) == N½O5 (2) c. N,O5 (2) d. 202) + 8NO2 ) 2O2 + 2NO2 () == 4N,O5 (g) с. e N2O5 == ¼ O2 (2) + NO2 (2) (3) e.
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