Write the given third order linear equation as an equivalent system of first order equations with initial values. S (1 − t²) y' − (4y" + 3 cos(t)y") = −3 sin(t) \y(3) = −3,_y′(3) = −2,_y'(3) = −2 Use Y1 = Y, y2 = y', and y3 = y". Y' = with initial values Y + Y -18 If you don't get this in 3 tries, you can get a hint.
Write the given third order linear equation as an equivalent system of first order equations with initial values. S (1 − t²) y' − (4y" + 3 cos(t)y") = −3 sin(t) \y(3) = −3,_y′(3) = −2,_y'(3) = −2 Use Y1 = Y, y2 = y', and y3 = y". Y' = with initial values Y + Y -18 If you don't get this in 3 tries, you can get a hint.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Write the given third order linear equation as an equivalent system of first order equations with initial values.
ƒ (1 − t²) y' — (4y"" + 3 cos(t)y") = −3 sin(t)
-
\y(3) = −3, _y'(3) = −2, y″(3) = -2
Use
Y'
Y1 = Y,
with initial values
Y
Y2 = y', and
(0)
Y3 =y".
Y+
16
If you don't get this in 3 tries, you can get a hint.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2cd2d665-daee-46b8-ac4c-2b4cec66538a%2F5f1d057b-7526-4198-961f-edfca1db44a0%2Fbe2h4a_processed.png&w=3840&q=75)
Transcribed Image Text:Write the given third order linear equation as an equivalent system of first order equations with initial values.
ƒ (1 − t²) y' — (4y"" + 3 cos(t)y") = −3 sin(t)
-
\y(3) = −3, _y'(3) = −2, y″(3) = -2
Use
Y'
Y1 = Y,
with initial values
Y
Y2 = y', and
(0)
Y3 =y".
Y+
16
If you don't get this in 3 tries, you can get a hint.
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