Write the given third order linear equation as an equivalent system of first order equations with initial values. 2y" ty" - y' sin(t) = cos(t) with y(-3) = 2, y'(-3) = 2, y'(-3) = −3 Use x₁ = y, x₂ = y, and x3 =y". = 0 0 sin t with initial values 1 = 1 0 -t 2 2 -3 0 1 0 x + If you don't get this in 2 tries, you can get a hint. 0 0
Write the given third order linear equation as an equivalent system of first order equations with initial values. 2y" ty" - y' sin(t) = cos(t) with y(-3) = 2, y'(-3) = 2, y'(-3) = −3 Use x₁ = y, x₂ = y, and x3 =y". = 0 0 sin t with initial values 1 = 1 0 -t 2 2 -3 0 1 0 x + If you don't get this in 2 tries, you can get a hint. 0 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Write the given third order linear equation as an equivalent system of first order equations with initial values.
2y" ty" y' sin(t) = cos(t)
with
y(-3) = 2, y'(-3) = 2, y'(-3) = −3
Use x₁ = y, x₂ = y', and x3 =y".
=
0
0
-
sin t
with initial values
1 =
1
0
-t
2
2
-3
0
1
0
x +
If you don't get this in 2 tries, you can get a hint.
0
0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ad229d2-94c2-4360-b0ca-273c76ee826c%2F7cde33dd-9bf2-4e4f-816a-5712fb9f6093%2Ffaavij7_processed.png&w=3840&q=75)
Transcribed Image Text:Write the given third order linear equation as an equivalent system of first order equations with initial values.
2y" ty" y' sin(t) = cos(t)
with
y(-3) = 2, y'(-3) = 2, y'(-3) = −3
Use x₁ = y, x₂ = y', and x3 =y".
=
0
0
-
sin t
with initial values
1 =
1
0
-t
2
2
-3
0
1
0
x +
If you don't get this in 2 tries, you can get a hint.
0
0
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