Write the given expression as an algebraic expression in x. sin(블 cos-1,

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Educational Content: Transforming Trigonometric Expressions**

**Objective:**
Understand how to convert a trigonometric expression into an algebraic expression.

**Problem Statement:**
Write the given expression as an algebraic expression in \( x \).

**Expression:**
\[
\sin\left(\frac{1}{2} \cos^{-1} x\right)
\]

### Explanation

To solve this problem, we are working with the inverse cosine function \(\cos^{-1}(x)\) and the sine of half that angle. We need to express this entirely in terms of \( x \).

1. **Understanding the Inverse Function and Half-Angle:**  
   - The \(\cos^{-1}(x)\) gives us an angle \(\theta\) such that \(\cos(\theta) = x\).
   - We want to find \(\sin\left(\frac{\theta}{2}\right)\).

2. **Apply the Half-Angle Identity for Sine:**

   The equation for the sine of a half-angle is:
   \[
   \sin\left(\frac{\theta}{2}\right) = \sqrt{\frac{1 - \cos(\theta)}{2}}
   \]

   We know that \(\cos(\theta) = x\), so substituting gives:
   \[
   \sin\left(\frac{1}{2} \cos^{-1} x\right) = \sqrt{\frac{1 - x}{2}}
   \]

### Conclusion

The given trigonometric expression \(\sin\left(\frac{1}{2} \cos^{-1} x\right)\) can be rewritten as the algebraic expression:
\[
\sqrt{\frac{1 - x}{2}}
\]

This expression provides an algebraic representation of the problem in terms of \( x \).
Transcribed Image Text:**Educational Content: Transforming Trigonometric Expressions** **Objective:** Understand how to convert a trigonometric expression into an algebraic expression. **Problem Statement:** Write the given expression as an algebraic expression in \( x \). **Expression:** \[ \sin\left(\frac{1}{2} \cos^{-1} x\right) \] ### Explanation To solve this problem, we are working with the inverse cosine function \(\cos^{-1}(x)\) and the sine of half that angle. We need to express this entirely in terms of \( x \). 1. **Understanding the Inverse Function and Half-Angle:** - The \(\cos^{-1}(x)\) gives us an angle \(\theta\) such that \(\cos(\theta) = x\). - We want to find \(\sin\left(\frac{\theta}{2}\right)\). 2. **Apply the Half-Angle Identity for Sine:** The equation for the sine of a half-angle is: \[ \sin\left(\frac{\theta}{2}\right) = \sqrt{\frac{1 - \cos(\theta)}{2}} \] We know that \(\cos(\theta) = x\), so substituting gives: \[ \sin\left(\frac{1}{2} \cos^{-1} x\right) = \sqrt{\frac{1 - x}{2}} \] ### Conclusion The given trigonometric expression \(\sin\left(\frac{1}{2} \cos^{-1} x\right)\) can be rewritten as the algebraic expression: \[ \sqrt{\frac{1 - x}{2}} \] This expression provides an algebraic representation of the problem in terms of \( x \).
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