ASK YOUR TEACHER The length of each of the two equal sides of an isosceles triangle is 26 meters (see figure). The angle between the two sides is 0. PRACTICE ANOTHER Ꮎ 26 m/ 26 m (a) Write the area of the triangle (in m2) as a function of = 2 A(을)= 0 -338 sin × m² 2 (b) Write the area of the triangle (in m2) as a function of 0. A(0) = = 338 sin 0 ✓ m² Determine the value of such that the area is a maximum. 元 0 = 2 You're right! Need Help? Read It 3 8

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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ASK YOUR TEACHER
The length of each of the two equal sides of an isosceles triangle is 26 meters (see figure). The angle between the two sides is 0.
PRACTICE ANOTHER
Ꮎ
26 m/
26 m
(a) Write the area of the triangle (in m2) as a function of
=
2
A(을)=
0
-338 sin
× m²
2
(b) Write the area of the triangle (in m2) as a function of 0.
A(0) =
= 338 sin 0
✓ m²
Determine the value of such that the area is a maximum.
元
0 =
2
You're right!
Need Help?
Read It
3
8
Transcribed Image Text:ASK YOUR TEACHER The length of each of the two equal sides of an isosceles triangle is 26 meters (see figure). The angle between the two sides is 0. PRACTICE ANOTHER Ꮎ 26 m/ 26 m (a) Write the area of the triangle (in m2) as a function of = 2 A(을)= 0 -338 sin × m² 2 (b) Write the area of the triangle (in m2) as a function of 0. A(0) = = 338 sin 0 ✓ m² Determine the value of such that the area is a maximum. 元 0 = 2 You're right! Need Help? Read It 3 8
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