Write the following numbers in a + bi form: -1 - 4i + i, -2 – 3i 1 -3 + i, 3i 4i =) (i)³ + i. +

Q: Divide (3 - 4i)/(4 + 3i) and express the result in standard form.

A: Multiply by the conjugate of the denominator

Q: Simplify the expression -i+ (7+ 8i) 2i(-6+2i) + - 1-i to the form a + y · i where a and y are real…

A: The given expression 2i-6+2i+-i+7+8i¯¯1-i. Simplify the expression 2i-6+2i+-i+7+8i¯¯1-i in standard…

Q: Simplify (6 - 3i) + [(4 - 2i) - (3 + i)].

A:

Q: Simplify the expression to a + bi form: (-6 – 9i)(-11 +7i)

A:

Q: (-2 + 7i) + (6 + 2i)

A: We have to find (-2 + 7i) + (6 + 2i)

Q: (-4+i)-(5-7i)² Simplify 3i

A: We use i2=-1

Q: (-7– 9i) + (10 + 10¿)

A: To simplify the given two complex number, add real part of first one with real part of second  and…

Q: -1+6i/-3-3i

A: Our Aim is to evaluate the expression given below:--1+6i-3-3i -(i)

Q: Determine the product of (1 + i) and (1–31) A) 4- 2i B) 2 + 4i c) 2- 2i D) 2-4i

A:

Q: Find the product and write the result in standard form (-7- 9i)(3+ i)

A: Given query is to find the the product of the complex numbers.

Q: Perform the operation and write the result in s (6+4i)(6-4i)

A:

Q: (5i)-(2i)-(8+4i) simplify

A: (5i)-(2i)-(8+4i) simplify

Q: (-1+i)-(-7+4i)-5

A: Simplify the expression (–1+i) – (–7+ 4i) – 5 as follows.(–1+ i) – (–7+ 4i) – 5 = –1+ i +7– 4 i – 5…

Q: (3 + 7i) 2 – 3i)

A: Follow next step

Q: ZA =(2+i) -(2-i) 4 4 4

A: z4=(2+i)4−(2−i)4

Q: (1-6i)/(-10+8i)

A: Let

Q: Perform the following difference and write the result in a + ib form. 2 + 3i 1 + 2i 8+i 3-i

A:

Q: AS: の4+o4i (3-i)(I-2i) (2+i)(1+2i)

A:

Q: erform the following ope (6+3i)(5-2i) a. (3i)*

A: # As per the guidelines we are entitled to solve one question at a time. Please resubmit the other…

Q: What is the difference of (-3+2i) and (6+3i)?

A:

Q: 6)(3і — 2) (4i — 5)

A: Given,

Q: Simplify the expression to a + bi form: (1+ 7i) + (4 – 10i) -

A: The given expression is 1+7i+4-10i.