Write the following numbers in a + bi form: () (а) —3 + i, (b) (-2 + 5i) – (1+ 5i) i, (c) + i, +

Q: Add / subtract: A) (-1+ 2i) + (-2 + 5i) B) (2-3i) - (-2+ 3i)

A:

Q: Divide (3 - 4i)/(4 + 3i) and express the result in standard form.

A: Multiply by the conjugate of the denominator

Q: Simplify the expression -i+ (7+ 8i) 2i(-6+2i) + - 1-i to the form a + y · i where a and y are real…

A: The given expression 2i-6+2i+-i+7+8i¯¯1-i. Simplify the expression 2i-6+2i+-i+7+8i¯¯1-i in standard…

Q: Simplify the expression to a + bi form: (-8 — 2:) + (8 — і)

A: (- 8 - 2i) + (8 - i) = (- 8 + 8) + (- 2i - i) = 0 + (- 3)i  So, a = 0 &, b = - 3

Q: Find the product and write the result in standard form (-7- 9i)(3+ i)

A: Given query is to find the the product of the complex numbers.

Q: Divide and express the result in standard form: (7 + 4i) / (2 - 5i).

A: 7+4i2-5i

Q: Divide and express the result in standard form: (5 + 4i) / (4 - i).

A: Given:5+4i4-i