Give only typing answer with explanation and conclusion Write the equilibrium equation for the forward reaction:2 CH4(g) + 3O2(g) 2 CO(g) + 4H₂O(g)1OKp[PCH₂12 [PO₂1³[PCO² [PH₂014[PCO2 [PH₂014Kp [FCH₂2 [PO₂13³2[PCO] +4[PH₂O]Kp = 2[PCH₂] +3[P0₂]2[PCH₂] +3[P0₂]OK₂2[PCO] + 4[PH₂O]=

Equilibrium constant Kp for a reaction is defined as the product of the equilibrium partial pressure…

Write the equilibrium equation for the forward reaction: 2 CH4(g) + 302(g) 2 CO(g) + 4H₂O(g) Kp [PCH₂¹2 [PO₂¹³ [PCOR [PH₂014 [PCOR [PH₂014 Kp= [PCH₂2 [PO₂13 O 2[PCO] +4[PH₂O] Kp = 2[PCH₂] +3[P0₂] 2[PCH₂] +3[P0₂] OK₂2[PCol +4[PH₂O) =

Write the equilibrium equation for the forward reaction: 2 CH4(g) + 302(g) 2 CO(g) + 4H₂O(g) Kp [PCH₂¹2 [PO₂¹³ [PCOR [PH₂014 [PCOR [PH₂014 Kp= [PCH₂2 [PO₂13 O 2[PCO] +4[PH₂O] Kp = 2[PCH₂] +3[P0₂] 2[PCH₂] +3[P0₂] OK₂2[PCol +4[PH₂O) =

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter19: The Chemistry Of The Main-group Elements

Section: Chapter Questions

Problem 91QRT

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