Write the empirical formula for at least four ionic compounds that could be formed from the following ions: CH;CO, Pb*, co , Fe*

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Write the empirical formula for at least four ionic compounds that could be formed from the following ions in the attached image

**Task: Determining Empirical Formulas for Ionic Compounds**

**Objective:**
The goal is to write the empirical formula for at least four ionic compounds using the given ions.

**Given Ions:**
- Acetate ion: \( \text{CH}_3\text{CO}_2^- \)
- Lead(IV) ion: \( \text{Pb}^{4+} \)
- Carbonate ion: \( \text{CO}_3^{2-} \)
- Iron(III) ion: \( \text{Fe}^{3+} \)

**Process:**
An empirical formula represents the simplest whole-number ratio of ions in an ionic compound. To form a neutral compound, the total positive and negative charges should cancel each other out. Below are possible combinations:

1. **Lead(IV) acetate**: Combining \( \text{Pb}^{4+} \) and 4 \(\text{CH}_3\text{CO}_2^- \) to form \(\text{Pb(CH}_3\text{CO}_2)_4\).

2. **Iron(III) acetate**: Combining \( \text{Fe}^{3+} \) and 3 \(\text{CH}_3\text{CO}_2^- \) to form \(\text{Fe(CH}_3\text{CO}_2)_3\).

3. **Lead(IV) carbonate**: Combining \( \text{Pb}^{4+} \) with 2 \(\text{CO}_3^{2-} \) to form \(\text{Pb(CO}_3)_2\).

4. **Iron(III) carbonate**: Combining 2 \( \text{Fe}^{3+} \) with 3 \(\text{CO}_3^{2-} \) to form \(\text{Fe}_2\text{(CO}_3\text{)}_3\).

**Tips:**
- Ensure the total positive charge equals the total negative charge.
- Use subscripts to denote the number of ions required to balance the charges.
Transcribed Image Text:**Task: Determining Empirical Formulas for Ionic Compounds** **Objective:** The goal is to write the empirical formula for at least four ionic compounds using the given ions. **Given Ions:** - Acetate ion: \( \text{CH}_3\text{CO}_2^- \) - Lead(IV) ion: \( \text{Pb}^{4+} \) - Carbonate ion: \( \text{CO}_3^{2-} \) - Iron(III) ion: \( \text{Fe}^{3+} \) **Process:** An empirical formula represents the simplest whole-number ratio of ions in an ionic compound. To form a neutral compound, the total positive and negative charges should cancel each other out. Below are possible combinations: 1. **Lead(IV) acetate**: Combining \( \text{Pb}^{4+} \) and 4 \(\text{CH}_3\text{CO}_2^- \) to form \(\text{Pb(CH}_3\text{CO}_2)_4\). 2. **Iron(III) acetate**: Combining \( \text{Fe}^{3+} \) and 3 \(\text{CH}_3\text{CO}_2^- \) to form \(\text{Fe(CH}_3\text{CO}_2)_3\). 3. **Lead(IV) carbonate**: Combining \( \text{Pb}^{4+} \) with 2 \(\text{CO}_3^{2-} \) to form \(\text{Pb(CO}_3)_2\). 4. **Iron(III) carbonate**: Combining 2 \( \text{Fe}^{3+} \) with 3 \(\text{CO}_3^{2-} \) to form \(\text{Fe}_2\text{(CO}_3\text{)}_3\). **Tips:** - Ensure the total positive charge equals the total negative charge. - Use subscripts to denote the number of ions required to balance the charges.
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