C.Maximize:P = 3y1+ 4y2subject to the constraints7y1+ 11y2 s59y1 + 12y2 s 6y12 0, y2 20d.Maximize:P = 5y1 + 6y2subject to the constraints7y1+ 12y2 s 39y1+ 1ly2<4y12 0, y2 20O e.Maximize:P = 5y1 + 6y2subject to the constraints7yı+ 9y211y1+ 12y2Yı 2 0, y2 20 Write the dual problem of the following minimum problem.Minimize C= 3x1 + 4x2 subject to the constraints7x1 + 9x2 2511x1 + 12x22 6X1 2 0, X2 2 0a.Maximize:P = 5y1 + 6y2subject to the constraints7y1+ 1ly2<39y1+ 12y2yı 2 0, y2 20Ob.Maximize:P = 3y1+ 4y2subject to the constraints7y1+ 12y29y1+ 1ly2Y1 2 0, y2 20

We use the definition of conversion from primal to dual to solve this problem.

Answered: Write the dual problem of the following…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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The equality lines for the following constraints are shown in the graph below: 40x + 15y 120 25x + 40y < 200 -За + 12у 12 y 5 4 2 F 1. 4. 5 6. 7 8. The feasible region is the area represented by the letter A BCDE F G VI VI VI 3.
Consider the following minimum problem (see image below) Write the dual problem for the above minimum problem by selecting the appropriate number for each blank box shown below (Do not solve the dual problem).
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Use the simplex method and the Duality Principle to solve the following minimum problem: C = 14x₁ + 20x2 Minimize: Subject to the constraints: x₁ + 2x₂ ≥ 4 7x₁ + 6x2 ≥ 20 X1 ≥ 0 X2 ≥ 0 and using your final tableau answer the questions below by entering the correct answer in each blank box. Please enter fractions as 3/5, -4/7, and so on. x1 = x2 = C =
A farmer has 500 acres of available land and $100,000 to spend. He wants to plant the combination of crops which maximizes his profit. Complete parts (a) through (c). Profits and Constraints for Crops Potatoes Corn Number of Acres Cost (per acre) Profit (per acre) X₁ $320 $120 with Minimize subject to: y₁ +320y₂ 2 120. Y₁+1282 2 40 w = 500 y₁ + 100000 ₂ Y₁+224y > 60 Y₁ 20, y₂ 20 $128 $40 The farmer's estimated profit is $ (Simplity your answer.) Cabbage X3 $224 $60 S ≤ = Total 500 $100,000 Z (b) The solution to the dual problem can be interpreted as shadow profits. Use shadow profits to estimate the farmer's profit if land is cut to 400 acres but capital increases to $110,000.
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