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L.P. Model: Maximize Subject to: Z = 1X + 10Y 4X+3Y ≤ 36 2X+4Y ≤40 1Y 28 X,Y 20 1.) Plot and label the constraints C₁, C₂ and C3 (using the line drawing tool) on the provided graph. 2.) Using the point drawing tool, plot the point that maximizes the objective function. The optimum solution is: X= (round your response to two decimal places). Y= (round your response to two decimal places). Optimal solution value Z = (round your response to two decimal places). (C₁) (C₂) (C3)

L.P. Model: Maximize Subject to: Z = 1X + 10Y 4X+3Y ≤ 36 2X+4Y ≤40 1Y 28 X,Y 20 1.) Plot and label the constraints C₁, C₂ and C3 (using the line drawing tool) on the provided graph. 2.) Using the point drawing tool, plot the point that maximizes the objective function. The optimum solution is: X= (round your response to two decimal places). Y= (round your response to two decimal places). Optimal solution value Z = (round your response to two decimal places). (C₁) (C₂) (C3)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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L.P. Model: Maximize Subject to: Z = 1X + 10Y (C₁) (C₂) (C3) 4X+3Y ≤ 36 2X+4Y ≤40 1Y 28 X,Y 20 1.) Plot and label the constraints C₁, C₂ and C3 (using the line drawing tool) on the provided graph. 2.) Using the point drawing tool, plot the point that maximizes the objective function. The optimum solution is: X = (round your response to two decimal places). Y = (round your response to two decimal places). Optimal solution value Z = (round your response to two decimal places). 22- 20- 18- 16+ 14- 12- 10- 8- 6- 4- 2- 0- +++~ 1 0 2 4 6 8 . 10 12 14 16 18 20 22 X
Transcribed Image Text:L.P. Model: Maximize Subject to: Z = 1X + 10Y (C₁) (C₂) (C3) 4X+3Y ≤ 36 2X+4Y ≤40 1Y 28 X,Y 20 1.) Plot and label the constraints C₁, C₂ and C3 (using the line drawing tool) on the provided graph. 2.) Using the point drawing tool, plot the point that maximizes the objective function. The optimum solution is: X = (round your response to two decimal places). Y = (round your response to two decimal places). Optimal solution value Z = (round your response to two decimal places). 22- 20- 18- 16+ 14- 12- 10- 8- 6- 4- 2- 0- +++~ 1 0 2 4 6 8 . 10 12 14 16 18 20 22 X
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