**Neutralization Reaction Between Sulfuric Acid and Potassium Hydroxide****Balanced Reaction:**Write the balanced neutralization reaction that occurs between H₂SO₄ and KOH in aqueous solution. Phases are optional.**Neutralization Reaction:**\[ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \]**Calculation of Remaining Concentration:**Suppose 0.650 L of 0.480 M H₂SO₄ is mixed with 0.600 L of 0.250 M KOH. What concentration of sulfuric acid remains after neutralization?\[ \text{Concentration:} \_\_\_\_\_\_\_\_\_ \text{M H}_2\text{SO}_4 \]**Note:**In the context of a neutralization reaction, the objective is to determine the stoichiometry of the reactants and calculate the remaining concentration of the excess reactant after the reaction is complete.

H2SO4 is a strong acid and KOH is a strong base. So, they will react together to form salt and water. The balanced reaction is: H2SO4 (aq) + 2KOH (aq) → K2SO4 + 2H2O Initial moles of KOH = Molarity×Volume = 0.600L×0.250M = 0.150 moles Initial moles of H2SO4 = Molarity×Volume = 0.650L×0.480M = 0.312 moles Now, according to the reaction, to neutralize 1 mole of H2SO4, 2 moles of KOH are required. Thus, to neutralize 0.312 moles of H2SO4, KOH required is 0.312×2 moles = 0.624 moles of KOH But, we have only 0.150 moles of KOH, so KOH is the limiting reagent. Now, 2moles of KOH reacts with 1mol of H2SO4 or, 1 mol KOH reacts with 1/2 moles of H2SO4 So, 0.150 moles of KOH reacts with (1/2)×0.150 = 0.075 moles of H2SO4 Thus, moles of H2SO4 left after reaction = 0.312 moles - 0.075 moles = 0.237 moles Total volume of the solution = 0.600L + 0.650L = 1.25 L Thus, concentration of H2SO4 = 0.237 moles/1.25L = 0.190 M (approx.) Hence, the concentration of H2SO4 remains after neutralization is 0.190 M

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Write the balanced neutralization reaction that occurs between H,SO, and KOH in aqueous solution. Phases are optional. neutralization reaction: Suppose 0.650 L of 0.480 M H,So, is mixed with 0.600 L of 0.250 M KOH. What concentration of sulfuric acid remains after neutralization? concentration: M H,SO,

Write the balanced neutralization reaction that occurs between H,SO, and KOH in aqueous solution. Phases are optional. neutralization reaction: Suppose 0.650 L of 0.480 M H,So, is mixed with 0.600 L of 0.250 M KOH. What concentration of sulfuric acid remains after neutralization? concentration: M H,SO,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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