Calculate the molarity of 150.0 mL of sodium hydroxide solution needed to react with 65.7 mL of a 0.128 M solution of phosphoric acid. OA. 0.877 M Ов.0.168 м OC. 0.0974 M OD.0.0420 M OE. 0.0187 M OF. 0.0390 M OG. 0.0561 M OH.0.292 M
Calculate the molarity of 150.0 mL of sodium hydroxide solution needed to react with 65.7 mL of a 0.128 M solution of phosphoric acid. OA. 0.877 M Ов.0.168 м OC. 0.0974 M OD.0.0420 M OE. 0.0187 M OF. 0.0390 M OG. 0.0561 M OH.0.292 M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 1**
Calculate the molarity of 150.0 mL of sodium hydroxide solution needed to react with 65.7 mL of a 0.128 M solution of phosphoric acid.
- A. 0.877 M
- B. 0.128 M
- C. 0.0974 M
- D. 0.0420 M
- E. 0.0187 M
- F. 0.0390 M
- G. 0.0564 M
- H. 0.292 M
**Question 2**
What volume of 0.128 M solution of hydrochloric acid is needed to react with 200.0 mL of 0.128 M calcium hydroxide?
- A. 0.0000410 mL
- B. 100 mL
- C. 0.00000419 mL
- D. 24400 mL
- E. 400 mL
- F. 0.00000819 mL
- G. 200 mL
- H. 6100 mL
**Question 3**
Given a density of 1.17 g/mL, what volume of a 50.5% solution of sulfuric acid is needed to react 350.0 mL of 0.138 M strontium hydroxide?
- A. 9.56 mL
- B. 13100 mL
- C. 5.15 mL
- D. 60.2 mL
- E. 3.8 mL
- F. 8.02 mL
- G. 13500 mL
- H. 4.40 mL
**Question 4**
Given 200.0 mL of a 0.139 M solution of aluminum chloride, according to the following equation, how many mL of a 0.358 M solution of sodium carbonate are needed to react with the aluminum chloride?
\[ 3 \text{ Na}_2\text{CO}_3(\text{aq}) + 2 \text{ AlCl}_3(\text{aq}) \rightarrow \text{ Al}_2(\text{CO}_3)_3(\text{s}) + 6 \text{ NaCl}(\text{aq}) \]
- A. 77.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1bfdb6c6-6fc3-4de6-b47d-25e0ae945ba0%2Fe481cd0e-f97f-4315-902e-fb296ebea6c2%2Fzkrvdj_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 1**
Calculate the molarity of 150.0 mL of sodium hydroxide solution needed to react with 65.7 mL of a 0.128 M solution of phosphoric acid.
- A. 0.877 M
- B. 0.128 M
- C. 0.0974 M
- D. 0.0420 M
- E. 0.0187 M
- F. 0.0390 M
- G. 0.0564 M
- H. 0.292 M
**Question 2**
What volume of 0.128 M solution of hydrochloric acid is needed to react with 200.0 mL of 0.128 M calcium hydroxide?
- A. 0.0000410 mL
- B. 100 mL
- C. 0.00000419 mL
- D. 24400 mL
- E. 400 mL
- F. 0.00000819 mL
- G. 200 mL
- H. 6100 mL
**Question 3**
Given a density of 1.17 g/mL, what volume of a 50.5% solution of sulfuric acid is needed to react 350.0 mL of 0.138 M strontium hydroxide?
- A. 9.56 mL
- B. 13100 mL
- C. 5.15 mL
- D. 60.2 mL
- E. 3.8 mL
- F. 8.02 mL
- G. 13500 mL
- H. 4.40 mL
**Question 4**
Given 200.0 mL of a 0.139 M solution of aluminum chloride, according to the following equation, how many mL of a 0.358 M solution of sodium carbonate are needed to react with the aluminum chloride?
\[ 3 \text{ Na}_2\text{CO}_3(\text{aq}) + 2 \text{ AlCl}_3(\text{aq}) \rightarrow \text{ Al}_2(\text{CO}_3)_3(\text{s}) + 6 \text{ NaCl}(\text{aq}) \]
- A. 77.
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