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write out step by step how they got the k value

write out step by step how they got the k value

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hello, I'm just stuck on finding k value here on part a. Would write out step by step how they got the k value here of 0.121 hr-1.

at 2, 4, 6, and 12 hr after termination of the IV infusion and assayed for drug concentration. The results are shown in this table. Time after termination of Concentration (mg/L) the infusion (hr). 7.3 4 5.7 6. 4.5 12 2.2 a. What is the half-life of the drug in this patient? E/2 = 5.8 hT. Graphically: t2 Con be estimoted » -K (t3-4,) %3D Mathemati Cally: %3D e K (6-2) » K: 0.121 hi' 4.5 = 7.3 %3D Ey2 = 0.693 %3D 0.693 => ty = 5.73 hr ০.12। b. Calculate the plasma concentration at steady state (Cps) graphically and mathematically Grophi cally: CPes is the Y- intercept Pss = 9.25mg| 0.121 X2
Transcribed Image Text:at 2, 4, 6, and 12 hr after termination of the IV infusion and assayed for drug concentration. The results are shown in this table. Time after termination of Concentration (mg/L) the infusion (hr). 7.3 4 5.7 6. 4.5 12 2.2 a. What is the half-life of the drug in this patient? E/2 = 5.8 hT. Graphically: t2 Con be estimoted » -K (t3-4,) %3D Mathemati Cally: %3D e K (6-2) » K: 0.121 hi' 4.5 = 7.3 %3D Ey2 = 0.693 %3D 0.693 => ty = 5.73 hr ০.12। b. Calculate the plasma concentration at steady state (Cps) graphically and mathematically Grophi cally: CPes is the Y- intercept Pss = 9.25mg| 0.121 X2
Expert Solution
Step 1

Let us consider The value of Rate constant (k)  is unknown. We have only Time and Concentration table. From this table we have to calculate k value. 

To find the k value from the given data we have to perform rate law equation one by one and identify the most appropriate value among them.

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