write code and execute the code turning in test cases and source code) for the following two algorithms to raise an integer to an integer power assume in both cases that n, the exponent, is a power of 2:         Again, in case you don’t have any programming language at hand you can use pseudocode to solve the problem.   Algorithm 1   X**N = X* X**(N-1) X**0 = 1   Algorithm 2

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Design and implement (meaning write code and execute the code turning in test cases and source code) for the following two algorithms to raise an integer to an integer power assume in both cases that n, the exponent, is a power of 2:

 

      Again, in case you don’t have any programming language at hand you can use pseudocode to solve the problem.

 

Algorithm 1

 

X**N = X* X**(N-1)

X**0 = 1

 

Algorithm 2

 

n = 2**m

 

X**n = ((X**2)**2)**2…, etc. [NOTE: the symbol of power (**) is used m times here, i.e., X**8 =  ((X**2)**2)**2, because 8 = 2**3].

 

Which algorithm is more efficient with respect to the number of multiplications?

 

(5) Design and implement (meaning write code and execute the code turning in test cases and
source code) for the following two algorithms to raise an integer to an integer power assume
in both cases that n, the exponent, is a power of 2:
Again, in case you don't have any programming language at hand you can use pseudocode
to solve the problem.
1
Transcribed Image Text:(5) Design and implement (meaning write code and execute the code turning in test cases and source code) for the following two algorithms to raise an integer to an integer power assume in both cases that n, the exponent, is a power of 2: Again, in case you don't have any programming language at hand you can use pseudocode to solve the problem. 1
Algorithm 1
X**N=X* X**(N-1)
X**0=1
Algorithm 2
n = 2**m
X**n = ((X**2)**2)**2..., etc. [NOTE: the symbol of power (**) is used m times here,
i.e., X**8 = ((X**2)**2)**2, because 8 = 2**3].
Which algorithm is more efficient with respect to the number of multiplications?
Transcribed Image Text:Algorithm 1 X**N=X* X**(N-1) X**0=1 Algorithm 2 n = 2**m X**n = ((X**2)**2)**2..., etc. [NOTE: the symbol of power (**) is used m times here, i.e., X**8 = ((X**2)**2)**2, because 8 = 2**3]. Which algorithm is more efficient with respect to the number of multiplications?
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